Alice and Bob continue their games with piles of stones. There are a number of piles arranged in a row, and each pile has a positive integer number of stones piles[i]. The objective of the game is to end with the most stones.
Alice and Bob take turns, with Alice starting first.
\n\nOn each player's turn, that player can take all the stones in the first X remaining piles, where 1 <= X <= 2M. Then, we set M = max(M, X). Initially, M = 1.
The game continues until all the stones have been taken.
\n\nAssuming Alice and Bob play optimally, return the maximum number of stones Alice can get.
\n\n\n
Example 1:
\n\nInput: piles = [2,7,9,4,4]
\n\nOutput: 10
\n\nExplanation:
\n\n2 + 4 + 4 = 10 stones in total.2 + 7 = 9 stones in total.So we return 10 since it's larger.
\nExample 2:
\n\nInput: piles = [1,2,3,4,5,100]
\n\nOutput: 104
\n\n
Constraints:
\n\n1 <= piles.length <= 1001 <= piles[i] <= 104Alice 和 Bob 继续他们的石子游戏。许多堆石子 排成一行，每堆都有正整数颗石子 piles[i]。游戏以谁手中的石子最多来决出胜负。
Alice 和 Bob 轮流进行，Alice 先开始。最初，M = 1。
在每个玩家的回合中，该玩家可以拿走剩下的 前 X 堆的所有石子，其中 1 <= X <= 2M。然后，令 M = max(M, X)。
游戏一直持续到所有石子都被拿走。
\n\n假设 Alice 和 Bob 都发挥出最佳水平，返回 Alice 可以得到的最大数量的石头。
\n\n\n\n
示例 1：
\n\n\n输入：piles = [2,7,9,4,4]\n输出：10\n解释：如果一开始 Alice 取了一堆，Bob 取了两堆，然后 Alice 再取两堆。Alice 可以得到 2 + 4 + 4 = 10 堆。\n如果 Alice 一开始拿走了两堆，那么 Bob 可以拿走剩下的三堆。在这种情况下，Alice 得到 2 + 7 = 9 堆。返回 10，因为它更大。\n\n\n
示例 2:
\n\n\n输入：piles = [1,2,3,4,5,100]\n输出：104\n\n\n
\n\n
提示：
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