![\"\"](\"https://assets.leetcode.com/uploads/2024/03/29/3708-tc1.png\")
You are given a 2D array points and a string s where, points[i] represents the coordinates of point i, and s[i] represents the tag of point i.
A valid square is a square centered at the origin (0, 0), has edges parallel to the axes, and does not contain two points with the same tag.
Return the maximum number of points contained in a valid square.
\n\nNote:
\n\n\n
Example 1:
\n\n
Input: points = [[2,2],[-1,-2],[-4,4],[-3,1],[3,-3]], s = "abdca"
\n\nOutput: 2
\n\nExplanation:
\n\nThe square of side length 4 covers two points points[0] and points[1].
Example 2:
\n\n![\"\"](\"https://assets.leetcode.com/uploads/2024/03/29/3708-tc2.png\")
Input: points = [[1,1],[-2,-2],[-2,2]], s = "abb"
\n\nOutput: 1
\n\nExplanation:
\n\nThe square of side length 2 covers one point, which is points[0].
Example 3:
\n\nInput: points = [[1,1],[-1,-1],[2,-2]], s = "ccd"
\n\nOutput: 0
\n\nExplanation:
\n\nIt's impossible to make any valid squares centered at the origin such that it covers only one point among points[0] and points[1].
\n
Constraints:
\n\n1 <= s.length, points.length <= 105points[i].length == 2-109 <= points[i][0], points[i][1] <= 109s.length == points.lengthpoints consists of distinct coordinates.s consists only of lowercase English letters.给你一个二维数组 points 和一个字符串 s ，其中 points[i] 表示第 i 个点的坐标，s[i] 表示第 i 个点的 标签 。
如果一个正方形的中心在 (0, 0) ，所有边都平行于坐标轴，且正方形内 不 存在标签相同的两个点，那么我们称这个正方形是 合法 的。
请你返回 合法 正方形中可以包含的 最多 点数。
\n\n注意：
\n\n\n\n
示例 1：
\n\n
输入：points = [[2,2],[-1,-2],[-4,4],[-3,1],[3,-3]], s = \"abdca\"
\n\n输出：2
\n\n解释：
\n\n边长为 4 的正方形包含两个点 points[0] 和 points[1] 。
示例 2：
\n\n
输入：points = [[1,1],[-2,-2],[-2,2]], s = \"abb\"
\n\n输出：1
\n\n解释：
\n\n边长为 2 的正方形包含 1 个点 points[0] 。
示例 3：
\n\n输入：points = [[1,1],[-1,-1],[2,-2]], s = \"ccd\"
\n\n输出：0
\n\n解释：
\n\n任何正方形都无法只包含 points[0] 和 points[1] 中的一个点，所以合法正方形中都不包含任何点。
\n\n
提示：
\n\n1 <= s.length, points.length <= 105points[i].length == 2-109 <= points[i][0], points[i][1] <= 109s.length == points.lengthpoints 中的点坐标互不相同。s 只包含小写英文字母。(x, y) is max(abs(x), abs(y)) * 2.",
"Sort the points by max(abs(x), abs(y)) and try each edge length, check the included point tags."
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