Given a circular array nums, find the maximum absolute difference between adjacent elements.
Note: In a circular array, the first and last elements are adjacent.
\n\n\n
Example 1:
\n\nInput: nums = [1,2,4]
\n\nOutput: 3
\n\nExplanation:
\n\nBecause nums is circular, nums[0] and nums[2] are adjacent. They have the maximum absolute difference of |4 - 1| = 3.
Example 2:
\n\nInput: nums = [-5,-10,-5]
\n\nOutput: 5
\n\nExplanation:
\n\nThe adjacent elements nums[0] and nums[1] have the maximum absolute difference of |-5 - (-10)| = 5.
\n
Constraints:
\n\n2 <= nums.length <= 100-100 <= nums[i] <= 100给你一个 循环 数组 nums ，请你找出相邻元素之间的 最大 绝对差值。
注意：一个循环数组中，第一个元素和最后一个元素是相邻的。
\n\n\n\n
示例 1：
\n\n输入：nums = [1,2,4]
\n\n输出：3
\n\n解释：
\n\n由于 nums 是循环的，nums[0] 和 nums[2] 是相邻的，它们之间的绝对差值是最大值 |4 - 1| = 3 。
示例 2：
\n\n输入：nums = [-5,-10,-5]
\n\n输出：5
\n\n解释：
\n\n相邻元素 nums[0] 和 nums[1] 之间的绝对差值为最大值 |-5 - (-10)| = 5 。
\n\n
提示：
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