{ "data": { "question": { "questionId": "1079", "questionFrontendId": "1022", "categoryTitle": "Algorithms", "boundTopicId": 3365, "title": "Sum of Root To Leaf Binary Numbers", "titleSlug": "sum-of-root-to-leaf-binary-numbers", "content": "
You are given the root
of a binary tree where each node has a value 0
or 1
. Each root-to-leaf path represents a binary number starting with the most significant bit.
0 -> 1 -> 1 -> 0 -> 1
, then this could represent 01101
in binary, which is 13
.For all leaves in the tree, consider the numbers represented by the path from the root to that leaf. Return the sum of these numbers.
\n\nThe test cases are generated so that the answer fits in a 32-bits integer.
\n\n\n
Example 1:
\n\nInput: root = [1,0,1,0,1,0,1]\nOutput: 22\nExplanation: (100) + (101) + (110) + (111) = 4 + 5 + 6 + 7 = 22\n\n\n
Example 2:
\n\n\nInput: root = [0]\nOutput: 0\n\n\n
\n
Constraints:
\n\n[1, 1000]
.Node.val
is 0
or 1
.给出一棵二叉树,其上每个结点的值都是 0
或 1
。每一条从根到叶的路径都代表一个从最高有效位开始的二进制数。
0 -> 1 -> 1 -> 0 -> 1
,那么它表示二进制数 01101
,也就是 13
。对树上的每一片叶子,我们都要找出从根到该叶子的路径所表示的数字。
\n\n返回这些数字之和。题目数据保证答案是一个 32 位 整数。
\n\n\n\n
示例 1:
\n\n输入:root = [1,0,1,0,1,0,1]\n输出:22\n解释:(100) + (101) + (110) + (111) = 4 + 5 + 6 + 7 = 22\n\n\n
示例 2:
\n\n\n输入:root = [0]\n输出:0\n\n\n
\n\n
提示:
\n\n[1, 1000]
范围内Node.val
仅为 0
或 1
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