![\"example-1\"](\"https://assets.leetcode.com/uploads/2021/10/02/ex1.png\")
You are given an integer array nums of 2 * n integers. You need to partition nums into two arrays of length n to minimize the absolute difference of the sums of the arrays. To partition nums, put each element of nums into one of the two arrays.
Return the minimum possible absolute difference.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,9,7,3]\nOutput: 2\nExplanation: One optimal partition is: [3,9] and [7,3].\nThe absolute difference between the sums of the arrays is abs((3 + 9) - (7 + 3)) = 2.\n\n\n
Example 2:
\n\n\nInput: nums = [-36,36]\nOutput: 72\nExplanation: One optimal partition is: [-36] and [36].\nThe absolute difference between the sums of the arrays is abs((-36) - (36)) = 72.\n\n\n
Example 3:
\n![\"example-3\"](\"https://assets.leetcode.com/uploads/2021/10/02/ex3.png\")
\n\nInput: nums = [2,-1,0,4,-2,-9]\nOutput: 0\nExplanation: One optimal partition is: [2,4,-9] and [-1,0,-2].\nThe absolute difference between the sums of the arrays is abs((2 + 4 + -9) - (-1 + 0 + -2)) = 0.\n\n\n
\n
Constraints:
\n\n1 <= n <= 15nums.length == 2 * n-107 <= nums[i] <= 107给你一个长度为 2 * n 的整数数组。你需要将 nums 分成 两个 长度为 n 的数组，分别求出两个数组的和，并 最小化 两个数组和之 差的绝对值 。nums 中每个元素都需要放入两个数组之一。
请你返回 最小 的数组和之差。
\n\n\n\n
示例 1：
\n\n
输入：nums = [3,9,7,3]\n输出：2\n解释：最优分组方案是分成 [3,9] 和 [7,3] 。\n数组和之差的绝对值为 abs((3 + 9) - (7 + 3)) = 2 。\n\n\n
示例 2：
\n\n输入：nums = [-36,36]\n输出：72\n解释：最优分组方案是分成 [-36] 和 [36] 。\n数组和之差的绝对值为 abs((-36) - (36)) = 72 。\n\n\n
示例 3：
\n\n
输入：nums = [2,-1,0,4,-2,-9]\n输出：0\n解释：最优分组方案是分成 [2,4,-9] 和 [-1,0,-2] 。\n数组和之差的绝对值为 abs((2 + 4 + -9) - (-1 + 0 + -2)) = 0 。\n\n\n
\n\n
提示：
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"exampleTestcases": "[3,9,7,3]\n[-36,36]\n[2,-1,0,4,-2,-9]",
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