{ "data": { "question": { "questionId": "2651", "questionFrontendId": "2580", "categoryTitle": "Algorithms", "boundTopicId": 2144628, "title": "Count Ways to Group Overlapping Ranges", "titleSlug": "count-ways-to-group-overlapping-ranges", "content": "

You are given a 2D integer array ranges where ranges[i] = [starti, endi] denotes that all integers between starti and endi (both inclusive) are contained in the ith range.

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You are to split ranges into two (possibly empty) groups such that:

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Two ranges are said to be overlapping if there exists at least one integer that is present in both ranges.

\n\n\n\n

Return the total number of ways to split ranges into two groups. Since the answer may be very large, return it modulo 109 + 7.

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Example 1:

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\nInput: ranges = [[6,10],[5,15]]\nOutput: 2\nExplanation: \nThe two ranges are overlapping, so they must be in the same group.\nThus, there are two possible ways:\n- Put both the ranges together in group 1.\n- Put both the ranges together in group 2.\n
\n\n

Example 2:

\n\n
\nInput: ranges = [[1,3],[10,20],[2,5],[4,8]]\nOutput: 4\nExplanation: \nRanges [1,3], and [2,5] are overlapping. So, they must be in the same group.\nAgain, ranges [2,5] and [4,8] are also overlapping. So, they must also be in the same group. \nThus, there are four possible ways to group them:\n- All the ranges in group 1.\n- All the ranges in group 2.\n- Ranges [1,3], [2,5], and [4,8] in group 1 and [10,20] in group 2.\n- Ranges [1,3], [2,5], and [4,8] in group 2 and [10,20] in group 1.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "统计将重叠区间合并成组的方案数", "translatedContent": "

给你一个二维整数数组 ranges ,其中 ranges[i] = [starti, endi] 表示 starti 到 endi 之间(包括二者)的所有整数都包含在第 i 个区间中。

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你需要将 ranges 分成 两个 组(可以为空),满足:

\n\n\n\n

如果两个区间有至少 一个 公共整数,那么这两个区间是 有交集 的。

\n\n\n\n

请你返回将 ranges 划分成两个组的 总方案数 。由于答案可能很大,将它对 109 + 7 取余 后返回。

\n\n

 

\n\n

示例 1:

\n\n
输入:ranges = [[6,10],[5,15]]\n输出:2\n解释:\n两个区间有交集,所以它们必须在同一个组内。\n所以有两种方案:\n- 将两个区间都放在第 1 个组中。\n- 将两个区间都放在第 2 个组中。\n
\n\n

示例 2:

\n\n
输入:ranges = [[1,3],[10,20],[2,5],[4,8]]\n输出:4\n解释:\n区间 [1,3] 和 [2,5] 有交集,所以它们必须在同一个组中。\n同理,区间 [2,5] 和 [4,8] 也有交集,所以它们也必须在同一个组中。\n所以总共有 4 种分组方案:\n- 所有区间都在第 1 组。\n- 所有区间都在第 2 组。\n- 区间 [1,3] ,[2,5] 和 [4,8] 在第 1 个组中,[10,20] 在第 2 个组中。\n- 区间 [1,3] ,[2,5] 和 [4,8] 在第 2 个组中,[10,20] 在第 1 个组中。\n
\n\n

 

\n\n

提示:

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