You are given a 0-indexed integer array nums representing the initial positions of some marbles. You are also given two 0-indexed integer arrays moveFrom and moveTo of equal length.
Throughout moveFrom.length steps, you will change the positions of the marbles. On the ith step, you will move all marbles at position moveFrom[i] to position moveTo[i].
After completing all the steps, return the sorted list of occupied positions.
\n\nNotes:
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Example 1:
\n\n\nInput: nums = [1,6,7,8], moveFrom = [1,7,2], moveTo = [2,9,5]\nOutput: [5,6,8,9]\nExplanation: Initially, the marbles are at positions 1,6,7,8.\nAt the i = 0th step, we move the marbles at position 1 to position 2. Then, positions 2,6,7,8 are occupied.\nAt the i = 1st step, we move the marbles at position 7 to position 9. Then, positions 2,6,8,9 are occupied.\nAt the i = 2nd step, we move the marbles at position 2 to position 5. Then, positions 5,6,8,9 are occupied.\nAt the end, the final positions containing at least one marbles are [5,6,8,9].\n\n
Example 2:
\n\n\nInput: nums = [1,1,3,3], moveFrom = [1,3], moveTo = [2,2]\nOutput: [2]\nExplanation: Initially, the marbles are at positions [1,1,3,3].\nAt the i = 0th step, we move all the marbles at position 1 to position 2. Then, the marbles are at positions [2,2,3,3].\nAt the i = 1st step, we move all the marbles at position 3 to position 2. Then, the marbles are at positions [2,2,2,2].\nSince 2 is the only occupied position, we return [2].\n\n\n
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Constraints:
\n\n1 <= nums.length <= 1051 <= moveFrom.length <= 105moveFrom.length == moveTo.length1 <= nums[i], moveFrom[i], moveTo[i] <= 109moveFrom[i] at the moment we want to apply the ith move.Compiled with clang 11 using the latest C++ 17 standard.
Your code is compiled with level two optimization (-O2). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
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