{ "data": { "question": { "questionId": "2054", "questionFrontendId": "1942", "categoryTitle": "Algorithms", "boundTopicId": 888603, "title": "The Number of the Smallest Unoccupied Chair", "titleSlug": "the-number-of-the-smallest-unoccupied-chair", "content": "

There is a party where n friends numbered from 0 to n - 1 are attending. There is an infinite number of chairs in this party that are numbered from 0 to infinity. When a friend arrives at the party, they sit on the unoccupied chair with the smallest number.

\n\n\n\n

When a friend leaves the party, their chair becomes unoccupied at the moment they leave. If another friend arrives at that same moment, they can sit in that chair.

\n\n

You are given a 0-indexed 2D integer array times where times[i] = [arrivali, leavingi], indicating the arrival and leaving times of the ith friend respectively, and an integer targetFriend. All arrival times are distinct.

\n\n

Return the chair number that the friend numbered targetFriend will sit on.

\n\n

 

\n

Example 1:

\n\n
\nInput: times = [[1,4],[2,3],[4,6]], targetFriend = 1\nOutput: 1\nExplanation: \n- Friend 0 arrives at time 1 and sits on chair 0.\n- Friend 1 arrives at time 2 and sits on chair 1.\n- Friend 1 leaves at time 3 and chair 1 becomes empty.\n- Friend 0 leaves at time 4 and chair 0 becomes empty.\n- Friend 2 arrives at time 4 and sits on chair 0.\nSince friend 1 sat on chair 1, we return 1.\n
\n\n

Example 2:

\n\n
\nInput: times = [[3,10],[1,5],[2,6]], targetFriend = 0\nOutput: 2\nExplanation: \n- Friend 1 arrives at time 1 and sits on chair 0.\n- Friend 2 arrives at time 2 and sits on chair 1.\n- Friend 0 arrives at time 3 and sits on chair 2.\n- Friend 1 leaves at time 5 and chair 0 becomes empty.\n- Friend 2 leaves at time 6 and chair 1 becomes empty.\n- Friend 0 leaves at time 10 and chair 2 becomes empty.\nSince friend 0 sat on chair 2, we return 2.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "最小未被占据椅子的编号", "translatedContent": "

有 n 个朋友在举办一个派对，这些朋友从 0 到 n - 1 编号。派对里有 无数 张椅子，编号为 0 到 infinity 。当一个朋友到达派对时，他会占据 编号最小 且未被占据的椅子。

\n\n\n\n

当一个朋友离开派对时，他的椅子会立刻变成未占据状态。如果同一时刻有另一个朋友到达，可以立即占据这张椅子。

\n\n

给你一个下标从 0 开始的二维整数数组 times ，其中 times[i] = [arrivali, leavingi] 表示第 i 个朋友到达和离开的时刻，同时给你一个整数 targetFriend 。所有到达时间 互不相同 。

\n\n

请你返回编号为 targetFriend 的朋友占据的 椅子编号 。

\n\n

 

\n\n

示例 1：

\n\n
输入：times = [[1,4],[2,3],[4,6]], targetFriend = 1\n输出：1\n解释：\n- 朋友 0 时刻 1 到达，占据椅子 0 。\n- 朋友 1 时刻 2 到达，占据椅子 1 。\n- 朋友 1 时刻 3 离开，椅子 1 变成未占据。\n- 朋友 0 时刻 4 离开，椅子 0 变成未占据。\n- 朋友 2 时刻 4 到达，占据椅子 0 。\n朋友 1 占据椅子 1 ，所以返回 1 。\n
\n\n

示例 2：

\n\n
输入：times = [[3,10],[1,5],[2,6]], targetFriend = 0\n输出：2\n解释：\n- 朋友 1 时刻 1 到达，占据椅子 0 。\n- 朋友 2 时刻 2 到达，占据椅子 1 。\n- 朋友 0 时刻 3 到达，占据椅子 2 。\n- 朋友 1 时刻 5 离开，椅子 0 变成未占据。\n- 朋友 2 时刻 6 离开，椅子 1 变成未占据。\n- 朋友 0 时刻 10 离开，椅子 2 变成未占据。\n朋友 0 占据椅子 2 ，所以返回 2 。\n
\n\n

 

\n\n

提示：

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