{ "data": { "question": { "questionId": "2157", "questionFrontendId": "2030", "categoryTitle": "Algorithms", "boundTopicId": 1026588, "title": "Smallest K-Length Subsequence With Occurrences of a Letter", "titleSlug": "smallest-k-length-subsequence-with-occurrences-of-a-letter", "content": "

You are given a string s, an integer k, a letter letter, and an integer repetition.

\n\n

Return the lexicographically smallest subsequence of s of length k that has the letter letter appear at least repetition times. The test cases are generated so that the letter appears in s at least repetition times.

\n\n

A subsequence is a string that can be derived from another string by deleting some or no characters without changing the order of the remaining characters.

\n\n

A string a is lexicographically smaller than a string b if in the first position where a and b differ, string a has a letter that appears earlier in the alphabet than the corresponding letter in b.

\n\n

 

\n

Example 1:

\n\n
\nInput: s = "leet", k = 3, letter = "e", repetition = 1\nOutput: "eet"\nExplanation: There are four subsequences of length 3 that have the letter 'e' appear at least 1 time:\n- "lee" (from "leet")\n- "let" (from "leet")\n- "let" (from "leet")\n- "eet" (from "leet")\nThe lexicographically smallest subsequence among them is "eet".\n
\n\n

Example 2:

\n\"example-2\"\n
\nInput: s = "leetcode", k = 4, letter = "e", repetition = 2\nOutput: "ecde"\nExplanation: "ecde" is the lexicographically smallest subsequence of length 4 that has the letter "e" appear at least 2 times.\n
\n\n

Example 3:

\n\n
\nInput: s = "bb", k = 2, letter = "b", repetition = 2\nOutput: "bb"\nExplanation: "bb" is the only subsequence of length 2 that has the letter "b" appear at least 2 times.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "含特定字母的最小子序列", "translatedContent": "

给你一个字符串 s ,一个整数 k ,一个字母 letter 以及另一个整数 repetition

\n\n

返回 s 中长度为 k字典序最小 的子序列,该子序列同时应满足字母 letter 出现 至少 repetition 次。生成的测试用例满足 letters 中出现 至少 repetition 次。

\n\n

子序列 是由原字符串删除一些(或不删除)字符且不改变剩余字符顺序得到的剩余字符串。

\n\n

字符串 a 字典序比字符串 b 小的定义为:在 ab 出现不同字符的第一个位置上,字符串 a 的字符在字母表中的顺序早于字符串 b 的字符。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:s = \"leet\", k = 3, letter = \"e\", repetition = 1\n输出:\"eet\"\n解释:存在 4 个长度为 3 ,且满足字母 'e' 出现至少 1 次的子序列:\n- \"lee\"(\"leet\")\n- \"let\"(\"leet\")\n- \"let\"(\"leet\")\n- \"eet\"(\"leet\")\n其中字典序最小的子序列是 \"eet\" 。\n
\n\n

示例 2:

\n\n

\"example-2\"

\n\n
\n输入:s = \"leetcode\", k = 4, letter = \"e\", repetition = 2\n输出:\"ecde\"\n解释:\"ecde\" 是长度为 4 且满足字母 \"e\" 出现至少 2 次的字典序最小的子序列。\n
\n\n

示例 3:

\n\n
\n输入:s = \"bb\", k = 2, letter = \"b\", repetition = 2\n输出:\"bb\"\n解释:\"bb\" 是唯一一个长度为 2 且满足字母 \"b\" 出现至少 2 次的子序列。\n
\n\n

 

\n\n

提示:

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exact-integer? char? exact-integer? string?)\n\n )", "__typename": "CodeSnippetNode" }, { "lang": "Erlang", "langSlug": "erlang", "code": "-spec smallest_subsequence(S :: unicode:unicode_binary(), K :: integer(), Letter :: char(), Repetition :: integer()) -> unicode:unicode_binary().\nsmallest_subsequence(S, K, Letter, Repetition) ->\n .", "__typename": "CodeSnippetNode" }, { "lang": "Elixir", "langSlug": "elixir", "code": "defmodule Solution do\n @spec smallest_subsequence(s :: String.t, k :: integer, letter :: char, repetition :: integer) :: String.t\n def smallest_subsequence(s, k, letter, repetition) do\n\n end\nend", "__typename": "CodeSnippetNode" } ], "stats": "{\"totalAccepted\": \"1.6K\", \"totalSubmission\": \"4.6K\", \"totalAcceptedRaw\": 1582, \"totalSubmissionRaw\": 4588, \"acRate\": \"34.5%\"}", "hints": [ "Use stack. 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