{ "data": { "question": { "questionId": "969", "questionFrontendId": "933", "categoryTitle": "Algorithms", "boundTopicId": 2243, "title": "Number of Recent Calls", "titleSlug": "number-of-recent-calls", "content": "
You have a RecentCounter
class which counts the number of recent requests within a certain time frame.
Implement the RecentCounter
class:
RecentCounter()
Initializes the counter with zero recent requests.int ping(int t)
Adds a new request at time t
, where t
represents some time in milliseconds, and returns the number of requests that has happened in the past 3000
milliseconds (including the new request). Specifically, return the number of requests that have happened in the inclusive range [t - 3000, t]
.It is guaranteed that every call to ping
uses a strictly larger value of t
than the previous call.
\n
Example 1:
\n\n\nInput\n["RecentCounter", "ping", "ping", "ping", "ping"]\n[[], [1], [100], [3001], [3002]]\nOutput\n[null, 1, 2, 3, 3]\n\nExplanation\nRecentCounter recentCounter = new RecentCounter();\nrecentCounter.ping(1); // requests = [1], range is [-2999,1], return 1\nrecentCounter.ping(100); // requests = [1, 100], range is [-2900,100], return 2\nrecentCounter.ping(3001); // requests = [1, 100, 3001], range is [1,3001], return 3\nrecentCounter.ping(3002); // requests = [1, 100, 3001, 3002], range is [2,3002], return 3\n\n\n
\n
Constraints:
\n\n1 <= t <= 109
ping
with strictly increasing values of t
.104
calls will be made to ping
.写一个 RecentCounter
类来计算特定时间范围内最近的请求。
请你实现 RecentCounter
类:
RecentCounter()
初始化计数器,请求数为 0 。int ping(int t)
在时间 t
添加一个新请求,其中 t
表示以毫秒为单位的某个时间,并返回过去 3000
毫秒内发生的所有请求数(包括新请求)。确切地说,返回在 [t-3000, t]
内发生的请求数。保证 每次对 ping
的调用都使用比之前更大的 t
值。
\n\n
示例 1:
\n\n\n输入:\n[\"RecentCounter\", \"ping\", \"ping\", \"ping\", \"ping\"]\n[[], [1], [100], [3001], [3002]]\n输出:\n[null, 1, 2, 3, 3]\n\n解释:\nRecentCounter recentCounter = new RecentCounter();\nrecentCounter.ping(1); // requests = [1],范围是 [-2999,1],返回 1\nrecentCounter.ping(100); // requests = [1, 100],范围是 [-2900,100],返回 2\nrecentCounter.ping(3001); // requests = [1, 100, 3001],范围是 [1,3001],返回 3\nrecentCounter.ping(3002); // requests = [1, 100, 3001, 3002],范围是 [2,3002],返回 3\n\n\n
\n\n
提示:
\n\n1 <= t <= 109
ping
调用所使用的 t
值都 严格递增ping
方法 104
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