{ "data": { "question": { "questionId": "2831", "questionFrontendId": "2748", "categoryTitle": "Algorithms", "boundTopicId": 2317487, "title": "Number of Beautiful Pairs", "titleSlug": "number-of-beautiful-pairs", "content": "

You are given a 0-indexed integer array nums. A pair of indices i, j where 0 <= i < j < nums.length is called beautiful if the first digit of nums[i] and the last digit of nums[j] are coprime.

\n\n

Return the total number of beautiful pairs in nums.

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Two integers x and y are coprime if there is no integer greater than 1 that divides both of them. In other words, x and y are coprime if gcd(x, y) == 1, where gcd(x, y) is the greatest common divisor of x and y.

\n\n

 

\n

Example 1:

\n\n
\nInput: nums = [2,5,1,4]\nOutput: 5\nExplanation: There are 5 beautiful pairs in nums:\nWhen i = 0 and j = 1: the first digit of nums[0] is 2, and the last digit of nums[1] is 5. We can confirm that 2 and 5 are coprime, since gcd(2,5) == 1.\nWhen i = 0 and j = 2: the first digit of nums[0] is 2, and the last digit of nums[2] is 1. Indeed, gcd(2,1) == 1.\nWhen i = 1 and j = 2: the first digit of nums[1] is 5, and the last digit of nums[2] is 1. Indeed, gcd(5,1) == 1.\nWhen i = 1 and j = 3: the first digit of nums[1] is 5, and the last digit of nums[3] is 4. Indeed, gcd(5,4) == 1.\nWhen i = 2 and j = 3: the first digit of nums[2] is 1, and the last digit of nums[3] is 4. Indeed, gcd(1,4) == 1.\nThus, we return 5.\n
\n\n

Example 2:

\n\n
\nInput: nums = [11,21,12]\nOutput: 2\nExplanation: There are 2 beautiful pairs:\nWhen i = 0 and j = 1: the first digit of nums[0] is 1, and the last digit of nums[1] is 1. Indeed, gcd(1,1) == 1.\nWhen i = 0 and j = 2: the first digit of nums[0] is 1, and the last digit of nums[2] is 2. Indeed, gcd(1,2) == 1.\nThus, we return 2.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "美丽下标对的数目", "translatedContent": "

给你一个下标从 0 开始的整数数组 nums 。如果下标对 ij 满足 0 ≤ i < j < nums.length ,如果 nums[i]第一个数字nums[j]最后一个数字 互质 ,则认为 nums[i]nums[j] 是一组 美丽下标对

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返回 nums美丽下标对 的总数目。

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对于两个整数 xy ,如果不存在大于 1 的整数可以整除它们,则认为 xy 互质 。换而言之,如果 gcd(x, y) == 1 ,则认为 xy 互质,其中 gcd(x, y)xk 最大公因数

\n\n

 

\n\n

示例 1:

\n\n
\n输入:nums = [2,5,1,4]\n输出:5\n解释:nums 中共有 5 组美丽下标对:\ni = 0 和 j = 1 :nums[0] 的第一个数字是 2 ,nums[1] 的最后一个数字是 5 。2 和 5 互质,因此 gcd(2,5) == 1 。\ni = 0 和 j = 2 :nums[0] 的第一个数字是 2 ,nums[1] 的最后一个数字是 1 。2 和 5 互质,因此 gcd(2,1) == 1 。\ni = 1 和 j = 2 :nums[0] 的第一个数字是 5 ,nums[1] 的最后一个数字是 1 。2 和 5 互质,因此 gcd(5,1) == 1 。\ni = 1 和 j = 3 :nums[0] 的第一个数字是 5 ,nums[1] 的最后一个数字是 4 。2 和 5 互质,因此 gcd(5,4) == 1 。\ni = 2 和 j = 3 :nums[0] 的第一个数字是 1 ,nums[1] 的最后一个数字是 4 。2 和 5 互质,因此 gcd(1,4) == 1 。\n因此,返回 5 。\n
\n\n

示例 2:

\n\n
\n输入:nums = [11,21,12]\n输出:2\n解释:共有 2 组美丽下标对:\ni = 0 和 j = 1 :nums[0] 的第一个数字是 1 ,nums[1] 的最后一个数字是 1 。gcd(1,1) == 1 。\ni = 0 和 j = 2 :nums[0] 的第一个数字是 1 ,nums[1] 的最后一个数字是 2 。gcd(1,2) == 1 。\n因此,返回 2 。
\n\n

 

\n\n

提示:

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