You are given a 0-indexed integer array nums. You are also given an integer key, which is present in nums.
For every unique integer target in nums, count the number of times target immediately follows an occurrence of key in nums. In other words, count the number of indices i such that:
0 <= i <= nums.length - 2,nums[i] == key and,nums[i + 1] == target.Return the target with the maximum count. The test cases will be generated such that the target with maximum count is unique.
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Example 1:
\n\n\nInput: nums = [1,100,200,1,100], key = 1\nOutput: 100\nExplanation: For target = 100, there are 2 occurrences at indices 1 and 4 which follow an occurrence of key.\nNo other integers follow an occurrence of key, so we return 100.\n\n\n
Example 2:
\n\n\nInput: nums = [2,2,2,2,3], key = 2\nOutput: 2\nExplanation: For target = 2, there are 3 occurrences at indices 1, 2, and 3 which follow an occurrence of key.\nFor target = 3, there is only one occurrence at index 4 which follows an occurrence of key.\ntarget = 2 has the maximum number of occurrences following an occurrence of key, so we return 2.\n\n\n
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Constraints:
\n\n2 <= nums.length <= 10001 <= nums[i] <= 1000给你一个下标从 0 开始的整数数组 nums ，同时给你一个整数 key ，它在 nums 出现过。
统计 在 nums 数组中紧跟着 key 后面出现的不同整数 target 的出现次数。换言之，target 的出现次数为满足以下条件的 i 的数目：
0 <= i <= n - 2nums[i] == key 且nums[i + 1] == target 。请你返回出现 最多 次数的 target 。测试数据保证出现次数最多的 target 是唯一的。
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示例 1：
\n\n输入：nums = [1,100,200,1,100], key = 1\n输出：100\n解释：对于 target = 100 ，在下标 1 和 4 处出现过 2 次，且都紧跟着 key 。\n没有其他整数在 key 后面紧跟着出现，所以我们返回 100 。\n\n\n
示例 2：
\n\n输入：nums = [2,2,2,2,3], key = 2\n输出：2\n解释：对于 target = 2 ，在下标 1 ，2 和 3 处出现过 3 次，且都紧跟着 key 。\n对于 target = 3 ，在下标 4 出出现过 1 次，且紧跟着 key 。\ntarget = 2 是紧跟着 key 之后出现次数最多的数字，所以我们返回 2 。\n\n\n
\n\n
提示：
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