{ "data": { "question": { "questionId": "2825", "questionFrontendId": "2716", "categoryTitle": "Algorithms", "boundTopicId": 2292626, "title": "Minimize String Length", "titleSlug": "minimize-string-length", "content": "
Given a 0-indexed string s
, repeatedly perform the following operation any number of times:
i
in the string, and let c
be the character in position i
. Delete the closest occurrence of c
to the left of i
(if any) and the closest occurrence of c
to the right of i
(if any).Your task is to minimize the length of s
by performing the above operation any number of times.
Return an integer denoting the length of the minimized string.
\n\n\n
Example 1:
\n\n\nInput: s = "aaabc"\nOutput: 3\nExplanation: In this example, s is "aaabc". We can start by selecting the character 'a' at index 1. We then remove the closest 'a' to the left of index 1, which is at index 0, and the closest 'a' to the right of index 1, which is at index 2. After this operation, the string becomes "abc". Any further operation we perform on the string will leave it unchanged. Therefore, the length of the minimized string is 3.\n\n
Example 2:
\n\n\nInput: s = "cbbd"\nOutput: 3\nExplanation: For this we can start with character 'b' at index 1. There is no occurrence of 'b' to the left of index 1, but there is one to the right at index 2, so we delete the 'b' at index 2. The string becomes "cbd" and further operations will leave it unchanged. Hence, the minimized length is 3. \n\n\n
Example 3:
\n\n\nInput: s = "dddaaa"\nOutput: 2\nExplanation: For this, we can start with the character 'd' at index 1. The closest occurrence of a 'd' to its left is at index 0, and the closest occurrence of a 'd' to its right is at index 2. We delete both index 0 and 2, so the string becomes "daaa". In the new string, we can select the character 'a' at index 2. The closest occurrence of an 'a' to its left is at index 1, and the closest occurrence of an 'a' to its right is at index 3. We delete both of them, and the string becomes "da". We cannot minimize this further, so the minimized length is 2.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 100
s
contains only lowercase English letters给你一个下标从 0 开始的字符串 s
,重复执行下述操作 任意 次:
i
,并使 c
为字符串下标 i
处的字符。并在 i
左侧(如果有)和 右侧(如果有)各 删除 一个距离 i
最近 的字符 c
。请你通过执行上述操作任意次,使 s
的长度 最小化 。
返回一个表示 最小化 字符串的长度的整数。
\n\n\n\n
示例 1:
\n\n\n输入:s = \"aaabc\"\n输出:3\n解释:在这个示例中,s 等于 \"aaabc\" 。我们可以选择位于下标 1 处的字符 'a' 开始。接着删除下标 1 左侧最近的那个 'a'(位于下标 0)以及下标 1 右侧最近的那个 'a'(位于下标 2)。执行操作后,字符串变为 \"abc\" 。继续对字符串执行任何操作都不会改变其长度。因此,最小化字符串的长度是 3 。\n\n
示例 2:
\n\n\n输入:s = \"cbbd\"\n输出:3\n解释:我们可以选择位于下标 1 处的字符 'b' 开始。下标 1 左侧不存在字符 'b' ,但右侧存在一个字符 'b'(位于下标 2),所以会删除位于下标 2 的字符 'b' 。执行操作后,字符串变为 \"cbd\" 。继续对字符串执行任何操作都不会改变其长度。因此,最小化字符串的长度是 3 。\n\n
示例 3:
\n\n\n输入:s = \"dddaaa\"\n输出:2\n解释:我们可以选择位于下标 1 处的字符 'd' 开始。接着删除下标 1 左侧最近的那个 'd'(位于下标 0)以及下标 1 右侧最近的那个 'd'(位于下标 2)。执行操作后,字符串变为 \"daaa\" 。继续对新字符串执行操作,可以选择位于下标 2 的字符 'a' 。接着删除下标 2 左侧最近的那个 'a'(位于下标 1)以及下标 2 右侧最近的那个 'a'(位于下标 3)。执行操作后,字符串变为 \"da\" 。继续对字符串执行任何操作都不会改变其长度。因此,最小化字符串的长度是 2 。\n\n\n
\n\n
提示:
\n\n1 <= s.length <= 100
s
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use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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rust 1.58.1<\\/code><\\/p>\\r\\n\\r\\n
PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n