There are n points on a road you are driving your taxi on. The n points on the road are labeled from 1 to n in the direction you are going, and you want to drive from point 1 to point n to make money by picking up passengers. You cannot change the direction of the taxi.
The passengers are represented by a 0-indexed 2D integer array rides, where rides[i] = [starti, endi, tipi] denotes the ith passenger requesting a ride from point starti to point endi who is willing to give a tipi dollar tip.
For each passenger i you pick up, you earn endi - starti + tipi dollars. You may only drive at most one passenger at a time.
Given n and rides, return the maximum number of dollars you can earn by picking up the passengers optimally.
Note: You may drop off a passenger and pick up a different passenger at the same point.
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Example 1:
\n\n\nInput: n = 5, rides = [[2,5,4],[1,5,1]]\nOutput: 7\nExplanation: We can pick up passenger 0 to earn 5 - 2 + 4 = 7 dollars.\n\n\n
Example 2:
\n\n\nInput: n = 20, rides = [[1,6,1],[3,10,2],[10,12,3],[11,12,2],[12,15,2],[13,18,1]]\nOutput: 20\nExplanation: We will pick up the following passengers:\n- Drive passenger 1 from point 3 to point 10 for a profit of 10 - 3 + 2 = 9 dollars.\n- Drive passenger 2 from point 10 to point 12 for a profit of 12 - 10 + 3 = 5 dollars.\n- Drive passenger 5 from point 13 to point 18 for a profit of 18 - 13 + 1 = 6 dollars.\nWe earn 9 + 5 + 6 = 20 dollars in total.\n\n
\n
Constraints:
\n\n1 <= n <= 1051 <= rides.length <= 3 * 104rides[i].length == 31 <= starti < endi <= n1 <= tipi <= 105你驾驶出租车行驶在一条有 n 个地点的路上。这 n 个地点从近到远编号为 1 到 n ，你想要从 1 开到 n ，通过接乘客订单盈利。你只能沿着编号递增的方向前进，不能改变方向。
乘客信息用一个下标从 0 开始的二维数组 rides 表示，其中 rides[i] = [starti, endi, tipi] 表示第 i 位乘客需要从地点 starti 前往 endi ，愿意支付 tipi 元的小费。
每一位 你选择接单的乘客 i ，你可以 盈利 endi - starti + tipi 元。你同时 最多 只能接一个订单。
给你 n 和 rides ，请你返回在最优接单方案下，你能盈利 最多 多少元。
注意：你可以在一个地点放下一位乘客，并在同一个地点接上另一位乘客。
\n\n\n\n
示例 1：
\n\n输入：n = 5, rides = [[2,5,4],[1,5,1]]\n输出：7\n解释：我们可以接乘客 0 的订单，获得 5 - 2 + 4 = 7 元。\n\n\n
示例 2：
\n\n输入：n = 20, rides = [[1,6,1],[3,10,2],[10,12,3],[11,12,2],[12,15,2],[13,18,1]]\n输出：20\n解释：我们可以接以下乘客的订单：\n- 将乘客 1 从地点 3 送往地点 10 ，获得 10 - 3 + 2 = 9 元。\n- 将乘客 2 从地点 10 送往地点 12 ，获得 12 - 10 + 3 = 5 元。\n- 将乘客 5 从地点 13 送往地点 18 ，获得 18 - 13 + 1 = 6 元。\n我们总共获得 9 + 5 + 6 = 20 元。\n\n
\n\n
提示：
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collections<\\/a>\\u3002\\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u6ce8\\u610f Python 2.7 \\u5c06\\u57282020\\u5e74\\u540e\\u4e0d\\u518d\\u7ef4\\u62a4<\\/a>\\u3002 \\u5982\\u60f3\\u4f7f\\u7528\\u6700\\u65b0\\u7248\\u7684Python\\uff0c\\u8bf7\\u9009\\u62e9Python 3\\u3002<\\/p>\"],\"c\":[\"C\",\" \\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n 1. 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