{ "data": { "question": { "questionId": "2134", "questionFrontendId": "2024", "categoryTitle": "Algorithms", "boundTopicId": 1026061, "title": "Maximize the Confusion of an Exam", "titleSlug": "maximize-the-confusion-of-an-exam", "content": "
A teacher is writing a test with n
true/false questions, with 'T'
denoting true and 'F'
denoting false. He wants to confuse the students by maximizing the number of consecutive questions with the same answer (multiple trues or multiple falses in a row).
You are given a string answerKey
, where answerKey[i]
is the original answer to the ith
question. In addition, you are given an integer k
, the maximum number of times you may perform the following operation:
'T'
or 'F'
(i.e., set answerKey[i]
to 'T'
or 'F'
).Return the maximum number of consecutive 'T'
s or 'F'
s in the answer key after performing the operation at most k
times.
\n
Example 1:
\n\n\nInput: answerKey = "TTFF", k = 2\nOutput: 4\nExplanation: We can replace both the 'F's with 'T's to make answerKey = "TTTT".\nThere are four consecutive 'T's.\n\n\n
Example 2:
\n\n\nInput: answerKey = "TFFT", k = 1\nOutput: 3\nExplanation: We can replace the first 'T' with an 'F' to make answerKey = "FFFT".\nAlternatively, we can replace the second 'T' with an 'F' to make answerKey = "TFFF".\nIn both cases, there are three consecutive 'F's.\n\n\n
Example 3:
\n\n\nInput: answerKey = "TTFTTFTT", k = 1\nOutput: 5\nExplanation: We can replace the first 'F' to make answerKey = "TTTTTFTT"\nAlternatively, we can replace the second 'F' to make answerKey = "TTFTTTTT". \nIn both cases, there are five consecutive 'T's.\n\n\n
\n
Constraints:
\n\nn == answerKey.length
1 <= n <= 5 * 104
answerKey[i]
is either 'T'
or 'F'
1 <= k <= n
一位老师正在出一场由 n
道判断题构成的考试,每道题的答案为 true (用 'T'
表示)或者 false (用 'F'
表示)。老师想增加学生对自己做出答案的不确定性,方法是 最大化 有 连续相同 结果的题数。(也就是连续出现 true 或者连续出现 false)。
给你一个字符串 answerKey
,其中 answerKey[i]
是第 i
个问题的正确结果。除此以外,还给你一个整数 k
,表示你能进行以下操作的最多次数:
'T'
或者 'F'
(也就是将 answerKey[i]
改为 'T'
或者 'F'
)。请你返回在不超过 k
次操作的情况下,最大 连续 'T'
或者 'F'
的数目。
\n\n
示例 1:
\n\n\n输入:answerKey = \"TTFF\", k = 2\n输出:4\n解释:我们可以将两个 'F' 都变为 'T' ,得到 answerKey = \"TTTT\" 。\n总共有四个连续的 'T' 。\n\n\n
示例 2:
\n\n\n输入:answerKey = \"TFFT\", k = 1\n输出:3\n解释:我们可以将最前面的 'T' 换成 'F' ,得到 answerKey = \"FFFT\" 。\n或者,我们可以将第二个 'T' 换成 'F' ,得到 answerKey = \"TFFF\" 。\n两种情况下,都有三个连续的 'F' 。\n\n\n
示例 3:
\n\n\n输入:answerKey = \"TTFTTFTT\", k = 1\n输出:5\n解释:我们可以将第一个 'F' 换成 'T' ,得到 answerKey = \"TTTTTFTT\" 。\n或者我们可以将第二个 'F' 换成 'T' ,得到 answerKey = \"TTFTTTTT\" 。\n两种情况下,都有五个连续的 'T' 。\n\n\n
\n\n
提示:
\n\nn == answerKey.length
1 <= n <= 5 * 104
answerKey[i]
要么是 'T'
,要么是 'F'
1 <= k <= n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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