{ "data": { "question": { "questionId": "676", "questionFrontendId": "676", "categoryTitle": "Algorithms", "boundTopicId": 1816, "title": "Implement Magic Dictionary", "titleSlug": "implement-magic-dictionary", "content": "
Design a data structure that is initialized with a list of different words. Provided a string, you should determine if you can change exactly one character in this string to match any word in the data structure.
\n\nImplement the MagicDictionary
class:
MagicDictionary()
Initializes the object.void buildDict(String[] dictionary)
Sets the data structure with an array of distinct strings dictionary
.bool search(String searchWord)
Returns true
if you can change exactly one character in searchWord
to match any string in the data structure, otherwise returns false
.\n
Example 1:
\n\n\nInput\n["MagicDictionary", "buildDict", "search", "search", "search", "search"]\n[[], [["hello", "leetcode"]], ["hello"], ["hhllo"], ["hell"], ["leetcoded"]]\nOutput\n[null, null, false, true, false, false]\n\nExplanation\nMagicDictionary magicDictionary = new MagicDictionary();\nmagicDictionary.buildDict(["hello", "leetcode"]);\nmagicDictionary.search("hello"); // return False\nmagicDictionary.search("hhllo"); // We can change the second 'h' to 'e' to match "hello" so we return True\nmagicDictionary.search("hell"); // return False\nmagicDictionary.search("leetcoded"); // return False\n\n\n
\n
Constraints:
\n\n1 <= dictionary.length <= 100
1 <= dictionary[i].length <= 100
dictionary[i]
consists of only lower-case English letters.dictionary
are distinct.1 <= searchWord.length <= 100
searchWord
consists of only lower-case English letters.buildDict
will be called only once before search
.100
calls will be made to search
.设计一个使用单词列表进行初始化的数据结构,单词列表中的单词 互不相同 。 如果给出一个单词,请判定能否只将这个单词中一个字母换成另一个字母,使得所形成的新单词存在于你构建的字典中。
\n\n实现 MagicDictionary
类:
MagicDictionary()
初始化对象void buildDict(String[] dictionary)
使用字符串数组 dictionary
设定该数据结构,dictionary
中的字符串互不相同bool search(String searchWord)
给定一个字符串 searchWord
,判定能否只将字符串中 一个 字母换成另一个字母,使得所形成的新字符串能够与字典中的任一字符串匹配。如果可以,返回 true
;否则,返回 false
。\n\n
示例:
\n\n\n输入\n[\"MagicDictionary\", \"buildDict\", \"search\", \"search\", \"search\", \"search\"]\n[[], [[\"hello\", \"leetcode\"]], [\"hello\"], [\"hhllo\"], [\"hell\"], [\"leetcoded\"]]\n输出\n[null, null, false, true, false, false]\n\n解释\nMagicDictionary magicDictionary = new MagicDictionary();\nmagicDictionary.buildDict([\"hello\", \"leetcode\"]);\nmagicDictionary.search(\"hello\"); // 返回 False\nmagicDictionary.search(\"hhllo\"); // 将第二个 'h' 替换为 'e' 可以匹配 \"hello\" ,所以返回 True\nmagicDictionary.search(\"hell\"); // 返回 False\nmagicDictionary.search(\"leetcoded\"); // 返回 False\n\n\n
\n\n
提示:
\n\n1 <= dictionary.length <= 100
1 <= dictionary[i].length <= 100
dictionary[i]
仅由小写英文字母组成dictionary
中的所有字符串 互不相同1 <= searchWord.length <= 100
searchWord
仅由小写英文字母组成buildDict
仅在 search
之前调用一次100
次 search
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
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out-of-bounds<\\/code>\\u548c
use-after-free<\\/code>\\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"
\\/debug:pdbonly<\\/code>)\\u3002<\\/p>\"],\"javascript\":[\"JavaScript\",\"
Node.js 16.13.2<\\/code><\\/p>\\r\\n\\r\\n
--harmony<\\/code> \\u6807\\u8bb0\\u6765\\u5f00\\u542f \\u65b0\\u7248ES6\\u7279\\u6027<\\/a>\\u3002<\\/p>\\r\\n\\r\\n
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PHP 8.1<\\/code>.<\\/p>\\r\\n\\r\\n