A peak element is an element that is strictly greater than its neighbors.
\n\nGiven an integer array nums, find a peak element, and return its index. If the array contains multiple peaks, return the index to any of the peaks.
You may imagine that nums[-1] = nums[n] = -∞.
You must write an algorithm that runs in O(log n) time.
\n
Example 1:
\n\n\nInput: nums = [1,2,3,1]\nOutput: 2\nExplanation: 3 is a peak element and your function should return the index number 2.\n\n
Example 2:
\n\n\nInput: nums = [1,2,1,3,5,6,4]\nOutput: 5\nExplanation: Your function can return either index number 1 where the peak element is 2, or index number 5 where the peak element is 6.\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1000-231 <= nums[i] <= 231 - 1nums[i] != nums[i + 1] for all valid i.峰值元素是指其值严格大于左右相邻值的元素。
\n\n给你一个整数数组 nums，找到峰值元素并返回其索引。数组可能包含多个峰值，在这种情况下，返回 任何一个峰值 所在位置即可。
你可以假设 nums[-1] = nums[n] = -∞ 。
你必须实现时间复杂度为 O(log n) 的算法来解决此问题。
\n\n
示例 1：
\n\n\n输入：nums = [1,2,3,1]\n输出：2\n解释：3 是峰值元素，你的函数应该返回其索引 2。\n\n示例 2：
\n\n\n输入：nums = [1,2,1,3,5,6,4]\n输出：1 或 5 \n解释：你的函数可以返回索引 1，其峰值元素为 2；\n 或者返回索引 5， 其峰值元素为 6。\n\n\n\n\n
提示：
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