You are given an array nums of non-negative integers and an integer k.
An array is called special if the bitwise OR of all of its elements is at least k.
Return the length of the shortest special non-empty subarray of nums, or return -1 if no special subarray exists.
\n
Example 1:
\n\nInput: nums = [1,2,3], k = 2
\n\nOutput: 1
\n\nExplanation:
\n\nThe subarray [3] has OR value of 3. Hence, we return 1.
Example 2:
\n\nInput: nums = [2,1,8], k = 10
\n\nOutput: 3
\n\nExplanation:
\n\nThe subarray [2,1,8] has OR value of 11. Hence, we return 3.
Example 3:
\n\nInput: nums = [1,2], k = 0
\n\nOutput: 1
\n\nExplanation:
\n\nThe subarray [1] has OR value of 1. Hence, we return 1.
\n
Constraints:
\n\n1 <= nums.length <= 2 * 1050 <= nums[i] <= 1090 <= k <= 109给你一个 非负 整数数组 nums 和一个整数 k 。
如果一个数组中所有元素的按位或运算 OR 的值 至少 为 k ，那么我们称这个数组是 特别的 。
请你返回 nums 中 最短特别非空 子数组的长度，如果特别子数组不存在，那么返回 -1 。
\n\n
示例 1：
\n\n输入：nums = [1,2,3], k = 2
\n\n输出：1
\n\n解释：
\n\n子数组 [3] 的按位 OR 值为 3 ，所以我们返回 1 。
示例 2：
\n\n输入：nums = [2,1,8], k = 10
\n\n输出：3
\n\n解释：
\n\n子数组 [2,1,8] 的按位 OR 值为 11 ，所以我们返回 3 。
示例 3：
\n\n输入：nums = [1,2], k = 0
\n\n输出：1
\n\n解释：
\n\n子数组 [1] 的按位 OR 值为 1 ，所以我们返回 1 。
\n\n
提示：
\n\n1 <= nums.length <= 2 * 1050 <= nums[i] <= 1090 <= k <= 109nums[i], we can maintain each subarray’s bitwise OR result ending with it.",
"The property of bitwise OR is that it never unsets any bits and only sets new bits",
"So the number of different results for each nums[i] is at most the number of bits 32."
],
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