You are given an integer array nums.
Return an integer that is the maximum distance between the indices of two (not necessarily different) prime numbers in nums.
\n
Example 1:
\n\nInput: nums = [4,2,9,5,3]
\n\nOutput: 3
\n\nExplanation: nums[1], nums[3], and nums[4] are prime. So the answer is |4 - 1| = 3.
Example 2:
\n\nInput: nums = [4,8,2,8]
\n\nOutput: 0
\n\nExplanation: nums[2] is prime. Because there is just one prime number, the answer is |2 - 2| = 0.
\n
Constraints:
\n\n1 <= nums.length <= 3 * 1051 <= nums[i] <= 100nums is at least one.给你一个整数数组 nums。
返回两个（不一定不同的）质数在 nums 中 下标 的 最大距离。
\n\n
示例 1：
\n\n输入： nums = [4,2,9,5,3]
\n\n输出： 3
\n\n解释： nums[1]、nums[3] 和 nums[4] 是质数。因此答案是 |4 - 1| = 3。
示例 2：
\n\n输入： nums = [4,8,2,8]
\n\n输出： 0
\n\n解释： nums[2] 是质数。因为只有一个质数，所以答案是 |2 - 2| = 0。
\n\n
提示：
\n\n1 <= nums.length <= 3 * 1051 <= nums[i] <= 100nums 中至少有一个质数。nums.",
"Find the first and the last prime number in the nums."
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"sampleTestCase": "[4,2,9,5,3]",
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