{ "data": { "question": { "questionId": "79", "questionFrontendId": "79", "categoryTitle": "Algorithms", "boundTopicId": 1201, "title": "Word Search", "titleSlug": "word-search", "content": "
Given an m x n
grid of characters board
and a string word
, return true
if word
exists in the grid.
The word can be constructed from letters of sequentially adjacent cells, where adjacent cells are horizontally or vertically neighboring. The same letter cell may not be used more than once.
\n\n\n
Example 1:
\n\nInput: board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCCED"\nOutput: true\n\n\n
Example 2:
\n\nInput: board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "SEE"\nOutput: true\n\n\n
Example 3:
\n\nInput: board = [["A","B","C","E"],["S","F","C","S"],["A","D","E","E"]], word = "ABCB"\nOutput: false\n\n\n
\n
Constraints:
\n\nm == board.length
n = board[i].length
1 <= m, n <= 6
1 <= word.length <= 15
board
and word
consists of only lowercase and uppercase English letters.\n
Follow up: Could you use search pruning to make your solution faster with a larger board
?
给定一个 m x n
二维字符网格 board
和一个字符串单词 word
。如果 word
存在于网格中,返回 true
;否则,返回 false
。
单词必须按照字母顺序,通过相邻的单元格内的字母构成,其中“相邻”单元格是那些水平相邻或垂直相邻的单元格。同一个单元格内的字母不允许被重复使用。
\n\n\n\n
示例 1:
\n\n输入:board = [[\"A\",\"B\",\"C\",\"E\"],[\"S\",\"F\",\"C\",\"S\"],[\"A\",\"D\",\"E\",\"E\"]], word = \"ABCCED\"\n输出:true\n\n\n
示例 2:
\n\n输入:board = [[\"A\",\"B\",\"C\",\"E\"],[\"S\",\"F\",\"C\",\"S\"],[\"A\",\"D\",\"E\",\"E\"]], word = \"SEE\"\n输出:true\n\n\n
示例 3:
\n\n输入:board = [[\"A\",\"B\",\"C\",\"E\"],[\"S\",\"F\",\"C\",\"S\"],[\"A\",\"D\",\"E\",\"E\"]], word = \"ABCB\"\n输出:false\n\n\n
\n\n
提示:
\n\nm == board.length
n = board[i].length
1 <= m, n <= 6
1 <= word.length <= 15
board
和 word
仅由大小写英文字母组成\n\n
进阶:你可以使用搜索剪枝的技术来优化解决方案,使其在 board
更大的情况下可以更快解决问题?
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