Given a positive integer num, return true if num is a perfect square or false otherwise.
A perfect square is an integer that is the square of an integer. In other words, it is the product of some integer with itself.
\n\nYou must not use any built-in library function, such as sqrt.
\n
Example 1:
\n\n\nInput: num = 16\nOutput: true\nExplanation: We return true because 4 * 4 = 16 and 4 is an integer.\n\n\n
Example 2:
\n\n\nInput: num = 14\nOutput: false\nExplanation: We return false because 3.742 * 3.742 = 14 and 3.742 is not an integer.\n\n\n
\n
Constraints:
\n\n1 <= num <= 231 - 1给你一个正整数 num 。如果 num 是一个完全平方数，则返回 true ，否则返回 false 。
完全平方数 是一个可以写成某个整数的平方的整数。换句话说，它可以写成某个整数和自身的乘积。
\n\n不能使用任何内置的库函数，如 sqrt 。
\n\n
示例 1：
\n\n\n输入：num = 16\n输出：true\n解释：返回 true ，因为 4 * 4 = 16 且 4 是一个整数。\n\n\n
示例 2：
\n\n\n输入：num = 14\n输出：false\n解释：返回 false ，因为 3.742 * 3.742 = 14 但 3.742 不是一个整数。\n\n\n
\n\n
提示：
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