{ "data": { "question": { "questionId": "3630", "questionFrontendId": "3337", "categoryTitle": "Algorithms", "boundTopicId": 2965621, "title": "Total Characters in String After Transformations II", "titleSlug": "total-characters-in-string-after-transformations-ii", "content": "
You are given a string s
consisting of lowercase English letters, an integer t
representing the number of transformations to perform, and an array nums
of size 26. In one transformation, every character in s
is replaced according to the following rules:
s[i]
with the next nums[s[i] - 'a']
consecutive characters in the alphabet. For example, if s[i] = 'a'
and nums[0] = 3
, the character 'a'
transforms into the next 3 consecutive characters ahead of it, which results in "bcd"
.'z'
. For example, if s[i] = 'y'
and nums[24] = 3
, the character 'y'
transforms into the next 3 consecutive characters ahead of it, which results in "zab"
.Return the length of the resulting string after exactly t
transformations.
Since the answer may be very large, return it modulo 109 + 7
.
\n
Example 1:
\n\nInput: s = "abcyy", t = 2, nums = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2]
\n\nOutput: 7
\n\nExplanation:
\n\nFirst Transformation (t = 1):
\n\n\t'a'
becomes 'b'
as nums[0] == 1
'b'
becomes 'c'
as nums[1] == 1
'c'
becomes 'd'
as nums[2] == 1
'y'
becomes 'z'
as nums[24] == 1
'y'
becomes 'z'
as nums[24] == 1
"bcdzz"
Second Transformation (t = 2):
\n\n\t'b'
becomes 'c'
as nums[1] == 1
'c'
becomes 'd'
as nums[2] == 1
'd'
becomes 'e'
as nums[3] == 1
'z'
becomes 'ab'
as nums[25] == 2
'z'
becomes 'ab'
as nums[25] == 2
"cdeabab"
Final Length of the string: The string is "cdeabab"
, which has 7 characters.
Example 2:
\n\nInput: s = "azbk", t = 1, nums = [2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2]
\n\nOutput: 8
\n\nExplanation:
\n\nFirst Transformation (t = 1):
\n\n\t'a'
becomes 'bc'
as nums[0] == 2
'z'
becomes 'ab'
as nums[25] == 2
'b'
becomes 'cd'
as nums[1] == 2
'k'
becomes 'lm'
as nums[10] == 2
"bcabcdlm"
Final Length of the string: The string is "bcabcdlm"
, which has 8 characters.
\n
Constraints:
\n\n1 <= s.length <= 105
s
consists only of lowercase English letters.1 <= t <= 109
nums.length == 26
1 <= nums[i] <= 25
给你一个由小写英文字母组成的字符串 s
,一个整数 t
表示要执行的 转换 次数,以及一个长度为 26 的数组 nums
。每次 转换 需要根据以下规则替换字符串 s
中的每个字符:
s[i]
替换为字母表中后续的 nums[s[i] - 'a']
个连续字符。例如,如果 s[i] = 'a'
且 nums[0] = 3
,则字符 'a'
转换为它后面的 3 个连续字符,结果为 \"bcd\"
。'z'
,则 回绕 到字母表的开头。例如,如果 s[i] = 'y'
且 nums[24] = 3
,则字符 'y'
转换为它后面的 3 个连续字符,结果为 \"zab\"
。返回 恰好 执行 t
次转换后得到的字符串的 长度。
由于答案可能非常大,返回其对 109 + 7
取余的结果。
\n\n
示例 1:
\n\n输入: s = \"abcyy\", t = 2, nums = [1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,2]
\n\n输出: 7
\n\n解释:
\n\n第一次转换 (t = 1)
\n\n\t'a'
变为 'b'
因为 nums[0] == 1
'b'
变为 'c'
因为 nums[1] == 1
'c'
变为 'd'
因为 nums[2] == 1
'y'
变为 'z'
因为 nums[24] == 1
'y'
变为 'z'
因为 nums[24] == 1
\"bcdzz\"
第二次转换 (t = 2)
\n\n\t'b'
变为 'c'
因为 nums[1] == 1
'c'
变为 'd'
因为 nums[2] == 1
'd'
变为 'e'
因为 nums[3] == 1
'z'
变为 'ab'
因为 nums[25] == 2
'z'
变为 'ab'
因为 nums[25] == 2
\"cdeabab\"
字符串最终长度: 字符串为 \"cdeabab\"
,长度为 7 个字符。
示例 2:
\n\n输入: s = \"azbk\", t = 1, nums = [2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2]
\n\n输出: 8
\n\n解释:
\n\n第一次转换 (t = 1)
\n\n\t'a'
变为 'bc'
因为 nums[0] == 2
'z'
变为 'ab'
因为 nums[25] == 2
'b'
变为 'cd'
因为 nums[1] == 2
'k'
变为 'lm'
因为 nums[10] == 2
\"bcabcdlm\"
字符串最终长度: 字符串为 \"bcabcdlm\"
,长度为 8 个字符。
\n\n
提示:
\n\n1 <= s.length <= 105
s
仅由小写英文字母组成。1 <= t <= 109
nums.length == 26
1 <= nums[i] <= 25
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