{ "data": { "question": { "questionId": "3629", "questionFrontendId": "3335", "categoryTitle": "Algorithms", "boundTopicId": 2965624, "title": "Total Characters in String After Transformations I", "titleSlug": "total-characters-in-string-after-transformations-i", "content": "
You are given a string s
and an integer t
, representing the number of transformations to perform. In one transformation, every character in s
is replaced according to the following rules:
'z'
, replace it with the string "ab"
.'a'
is replaced with 'b'
, 'b'
is replaced with 'c'
, and so on.Return the length of the resulting string after exactly t
transformations.
Since the answer may be very large, return it modulo 109 + 7
.
\n
Example 1:
\n\nInput: s = "abcyy", t = 2
\n\nOutput: 7
\n\nExplanation:
\n\n'a'
becomes 'b'
'b'
becomes 'c'
'c'
becomes 'd'
'y'
becomes 'z'
'y'
becomes 'z'
"bcdzz"
'b'
becomes 'c'
'c'
becomes 'd'
'd'
becomes 'e'
'z'
becomes "ab"
'z'
becomes "ab"
"cdeabab"
"cdeabab"
, which has 7 characters.Example 2:
\n\nInput: s = "azbk", t = 1
\n\nOutput: 5
\n\nExplanation:
\n\n'a'
becomes 'b'
'z'
becomes "ab"
'b'
becomes 'c'
'k'
becomes 'l'
"babcl"
"babcl"
, which has 5 characters.\n
Constraints:
\n\n1 <= s.length <= 105
s
consists only of lowercase English letters.1 <= t <= 105
给你一个字符串 s
和一个整数 t
,表示要执行的 转换 次数。每次 转换 需要根据以下规则替换字符串 s
中的每个字符:
'z'
,则将其替换为字符串 \"ab\"
。'a'
替换为 'b'
,'b'
替换为 'c'
,依此类推。返回 恰好 执行 t
次转换后得到的字符串的 长度。
由于答案可能非常大,返回其对 109 + 7
取余的结果。
\n\n
示例 1:
\n\n输入: s = \"abcyy\", t = 2
\n\n输出: 7
\n\n解释:
\n\n'a'
变为 'b'
'b'
变为 'c'
'c'
变为 'd'
'y'
变为 'z'
'y'
变为 'z'
\"bcdzz\"
'b'
变为 'c'
'c'
变为 'd'
'd'
变为 'e'
'z'
变为 \"ab\"
'z'
变为 \"ab\"
\"cdeabab\"
\"cdeabab\"
,长度为 7 个字符。示例 2:
\n\n输入: s = \"azbk\", t = 1
\n\n输出: 5
\n\n解释:
\n\n'a'
变为 'b'
'z'
变为 \"ab\"
'b'
变为 'c'
'k'
变为 'l'
\"babcl\"
\"babcl\"
,长度为 5 个字符。\n\n
提示:
\n\n1 <= s.length <= 105
s
仅由小写英文字母组成。1 <= t <= 105
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"exampleTestcases": "\"abcyy\"\n2\n\"azbk\"\n1",
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