In the town of Digitville, there was a list of numbers called nums containing integers from 0 to n - 1. Each number was supposed to appear exactly once in the list, however, two mischievous numbers sneaked in an additional time, making the list longer than usual.
As the town detective, your task is to find these two sneaky numbers. Return an array of size two containing the two numbers (in any order), so peace can return to Digitville.
\n\n\n
Example 1:
\n\nInput: nums = [0,1,1,0]
\n\nOutput: [0,1]
\n\nExplanation:
\n\nThe numbers 0 and 1 each appear twice in the array.
\nExample 2:
\n\nInput: nums = [0,3,2,1,3,2]
\n\nOutput: [2,3]
\n\nExplanation:
\n\nThe numbers 2 and 3 each appear twice in the array.
\nExample 3:
\n\nInput: nums = [7,1,5,4,3,4,6,0,9,5,8,2]
\n\nOutput: [4,5]
\n\nExplanation:
\n\nThe numbers 4 and 5 each appear twice in the array.
\n\n
Constraints:
\n\n2 <= n <= 100nums.length == n + 20 <= nums[i] < nnums contains exactly two repeated elements.数字小镇 Digitville 中，存在一个数字列表 nums，其中包含从 0 到 n - 1 的整数。每个数字本应 只出现一次，然而，有 两个 顽皮的数字额外多出现了一次，使得列表变得比正常情况下更长。
为了恢复 Digitville 的和平，作为小镇中的名侦探，请你找出这两个顽皮的数字。
\n\n返回一个长度为 2 的数组，包含这两个数字（顺序任意）。
\n\n\n\n
示例 1：
\n\n输入： nums = [0,1,1,0]
\n\n输出： [0,1]
\n\n解释：
\n\n数字 0 和 1 分别在数组中出现了两次。
\n示例 2：
\n\n输入： nums = [0,3,2,1,3,2]
\n\n输出： [2,3]
\n\n解释:
\n\n数字 2 和 3 分别在数组中出现了两次。
\n示例 3：
\n\n输入： nums = [7,1,5,4,3,4,6,0,9,5,8,2]
\n\n输出： [4,5]
\n\n解释:
\n\n数字 4 和 5 分别在数组中出现了两次。
\n\n\n
提示：
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