You are given a 0-indexed integer array nums. In one step, remove all elements nums[i] where nums[i - 1] > nums[i] for all 0 < i < nums.length.
Return the number of steps performed until nums becomes a non-decreasing array.
\n
Example 1:
\n\n\nInput: nums = [5,3,4,4,7,3,6,11,8,5,11]\nOutput: 3\nExplanation: The following are the steps performed:\n- Step 1: [5,3,4,4,7,3,6,11,8,5,11] becomes [5,4,4,7,6,11,11]\n- Step 2: [5,4,4,7,6,11,11] becomes [5,4,7,11,11]\n- Step 3: [5,4,7,11,11] becomes [5,7,11,11]\n[5,7,11,11] is a non-decreasing array. Therefore, we return 3.\n\n\n
Example 2:
\n\n\nInput: nums = [4,5,7,7,13]\nOutput: 0\nExplanation: nums is already a non-decreasing array. Therefore, we return 0.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1051 <= nums[i] <= 109给你一个下标从 0 开始的整数数组 nums 。在一步操作中，移除所有满足 nums[i - 1] > nums[i] 的 nums[i] ，其中 0 < i < nums.length 。
重复执行步骤，直到 nums 变为 非递减 数组，返回所需执行的操作数。
\n\n
示例 1：
\n\n\n输入：nums = [5,3,4,4,7,3,6,11,8,5,11]\n输出：3\n解释：执行下述几个步骤：\n- 步骤 1 ：[5,3,4,4,7,3,6,11,8,5,11] 变为 [5,4,4,7,6,11,11]\n- 步骤 2 ：[5,4,4,7,6,11,11] 变为 [5,4,7,11,11]\n- 步骤 3 ：[5,4,7,11,11] 变为 [5,7,11,11]\n[5,7,11,11] 是一个非递减数组，因此，返回 3 。\n\n\n
示例 2：
\n\n\n输入：nums = [4,5,7,7,13]\n输出：0\n解释：nums 已经是一个非递减数组，因此，返回 0 。\n\n\n
\n\n
提示：
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"exampleTestcases": "[5,3,4,4,7,3,6,11,8,5,11]\n[4,5,7,7,13]",
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