You are given two strings a and b of the same length. Choose an index and split both strings at the same index, splitting a into two strings: aprefix and asuffix where a = aprefix + asuffix, and splitting b into two strings: bprefix and bsuffix where b = bprefix + bsuffix. Check if aprefix + bsuffix or bprefix + asuffix forms a palindrome.
When you split a string s into sprefix and ssuffix, either ssuffix or sprefix is allowed to be empty. For example, if s = "abc", then "" + "abc", "a" + "bc", "ab" + "c" , and "abc" + "" are valid splits.
Return true if it is possible to form a palindrome string, otherwise return false.
Notice that x + y denotes the concatenation of strings x and y.
\n
Example 1:
\n\n\nInput: a = "x", b = "y"\nOutput: true\nExplaination: If either a or b are palindromes the answer is true since you can split in the following way:\naprefix = "", asuffix = "x"\nbprefix = "", bsuffix = "y"\nThen, aprefix + bsuffix = "" + "y" = "y", which is a palindrome.\n\n\n
Example 2:
\n\n\nInput: a = "xbdef", b = "xecab"\nOutput: false\n\n\n
Example 3:
\n\n\nInput: a = "ulacfd", b = "jizalu"\nOutput: true\nExplaination: Split them at index 3:\naprefix = "ula", asuffix = "cfd"\nbprefix = "jiz", bsuffix = "alu"\nThen, aprefix + bsuffix = "ula" + "alu" = "ulaalu", which is a palindrome.\n\n\n
\n
Constraints:
\n\n1 <= a.length, b.length <= 105a.length == b.lengtha and b consist of lowercase English letters给你两个字符串 a 和 b ，它们长度相同。请你选择一个下标，将两个字符串都在 相同的下标 分割开。由 a 可以得到两个字符串： aprefix 和 asuffix ，满足 a = aprefix + asuffix ，同理，由 b 可以得到两个字符串 bprefix 和 bsuffix ，满足 b = bprefix + bsuffix 。请你判断 aprefix + bsuffix 或者 bprefix + asuffix 能否构成回文串。
当你将一个字符串 s 分割成 sprefix 和 ssuffix 时， ssuffix 或者 sprefix 可以为空。比方说， s = \"abc\" 那么 \"\" + \"abc\" ， \"a\" + \"bc\" ， \"ab\" + \"c\" 和 \"abc\" + \"\" 都是合法分割。
如果 能构成回文字符串 ，那么请返回 true，否则返回 false 。
注意， x + y 表示连接字符串 x 和 y 。
\n\n
示例 1：
\n\n\n输入：a = \"x\", b = \"y\"\n输出：true\n解释：如果 a 或者 b 是回文串，那么答案一定为 true ，因为你可以如下分割：\naprefix = \"\", asuffix = \"x\"\nbprefix = \"\", bsuffix = \"y\"\n那么 aprefix + bsuffix = \"\" + \"y\" = \"y\" 是回文串。\n\n\n
示例 2：
\n\n\n输入：a = \"xbdef\", b = \"xecab\"\n输出：false\n\n\n
示例 3：
\n\n\n输入：a = \"ulacfd\", b = \"jizalu\"\n输出：true\n解释：在下标为 3 处分割：\naprefix = \"ula\", asuffix = \"cfd\"\nbprefix = \"jiz\", bsuffix = \"alu\"\n那么 aprefix + bsuffix = \"ula\" + \"alu\" = \"ulaalu\" 是回文串。\n\n
\n\n
提示：
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"exampleTestcases": "\"x\"\n\"y\"\n\"xbdef\"\n\"xecab\"\n\"ulacfd\"\n\"jizalu\"",
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