{ "data": { "question": { "questionId": "2737", "questionFrontendId": "2643", "categoryTitle": "Algorithms", "boundTopicId": 2226015, "title": "Row With Maximum Ones", "titleSlug": "row-with-maximum-ones", "content": "
Given a m x n
binary matrix mat
, find the 0-indexed position of the row that contains the maximum count of ones, and the number of ones in that row.
In case there are multiple rows that have the maximum count of ones, the row with the smallest row number should be selected.
\n\nReturn an array containing the index of the row, and the number of ones in it.
\n\n\n
Example 1:
\n\n\nInput: mat = [[0,1],[1,0]]\nOutput: [0,1]\nExplanation: Both rows have the same number of 1's. So we return the index of the smaller row, 0, and the maximum count of ones (1)
. So, the answer is [0,1]. \n
\n\nExample 2:
\n\n\nInput: mat = [[0,0,0],[0,1,1]]\nOutput: [1,2]\nExplanation: The row indexed 1 has the maximum count of ones\n\n(2)
. So we return its index,1
, and the count. So, the answer is [1,2].\n
Example 3:
\n\n\nInput: mat = [[0,0],[1,1],[0,0]]\nOutput: [1,2]\nExplanation: The row indexed 1 has the maximum count of ones (2). So the answer is [1,2].\n\n\n
\n
Constraints:
\n\nm == mat.length
n == mat[i].length
1 <= m, n <= 100
mat[i][j]
is either 0
or 1
.给你一个大小为 m x n
的二进制矩阵 mat
,请你找出包含最多 1 的行的下标(从 0 开始)以及这一行中 1 的数目。
如果有多行包含最多的 1 ,只需要选择 行下标最小 的那一行。
\n\n返回一个由行下标和该行中 1 的数量组成的数组。
\n\n\n\n
示例 1:
\n\n\n输入:mat = [[0,1],[1,0]]\n输出:[0,1]\n解释:两行中 1 的数量相同。所以返回下标最小的行,下标为 0 。该行 1 的数量为 1 。所以,答案为 [0,1] 。 \n\n\n
示例 2:
\n\n\n输入:mat = [[0,0,0],[0,1,1]]\n输出:[1,2]\n解释:下标为 1 的行中 1 的数量最多\n\n。
该行 1 的数量为 2 。所以,答案为
[1,2] 。\n
示例 3:
\n\n\n输入:mat = [[0,0],[1,1],[0,0]]\n输出:[1,2]\n解释:下标为 1 的行中 1 的数量最多。该行 1 的数量为 2 。所以,答案为
[1,2] 。
\n\n\n\n
提示:
\n\nm == mat.length
n == mat[i].length
1 <= m, n <= 100
mat[i][j]
为 0
或 1
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