{ "data": { "question": { "questionId": "26", "questionFrontendId": "26", "categoryTitle": "Algorithms", "boundTopicId": 1166, "title": "Remove Duplicates from Sorted Array", "titleSlug": "remove-duplicates-from-sorted-array", "content": "
Given an integer array nums
sorted in non-decreasing order, remove the duplicates in-place such that each unique element appears only once. The relative order of the elements should be kept the same. Then return the number of unique elements in nums
.
Consider the number of unique elements of nums
to be k
, to get accepted, you need to do the following things:
nums
such that the first k
elements of nums
contain the unique elements in the order they were present in nums
initially. The remaining elements of nums
are not important as well as the size of nums
.k
.Custom Judge:
\n\nThe judge will test your solution with the following code:
\n\n\nint[] nums = [...]; // Input array\nint[] expectedNums = [...]; // The expected answer with correct length\n\nint k = removeDuplicates(nums); // Calls your implementation\n\nassert k == expectedNums.length;\nfor (int i = 0; i < k; i++) {\n assert nums[i] == expectedNums[i];\n}\n\n\n
If all assertions pass, then your solution will be accepted.
\n\n\n
Example 1:
\n\n\nInput: nums = [1,1,2]\nOutput: 2, nums = [1,2,_]\nExplanation: Your function should return k = 2, with the first two elements of nums being 1 and 2 respectively.\nIt does not matter what you leave beyond the returned k (hence they are underscores).\n\n\n
Example 2:
\n\n\nInput: nums = [0,0,1,1,1,2,2,3,3,4]\nOutput: 5, nums = [0,1,2,3,4,_,_,_,_,_]\nExplanation: Your function should return k = 5, with the first five elements of nums being 0, 1, 2, 3, and 4 respectively.\nIt does not matter what you leave beyond the returned k (hence they are underscores).\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 3 * 104
-100 <= nums[i] <= 100
nums
is sorted in non-decreasing order.给你一个 非严格递增排列 的数组 nums
,请你 原地 删除重复出现的元素,使每个元素 只出现一次 ,返回删除后数组的新长度。元素的 相对顺序 应该保持 一致 。然后返回 nums
中唯一元素的个数。
考虑 nums
的唯一元素的数量为 k
,你需要做以下事情确保你的题解可以被通过:
nums
,使 nums
的前 k
个元素包含唯一元素,并按照它们最初在 nums
中出现的顺序排列。nums
的其余元素与 nums
的大小不重要。k
。判题标准:
\n\n系统会用下面的代码来测试你的题解:
\n\n\nint[] nums = [...]; // 输入数组\nint[] expectedNums = [...]; // 长度正确的期望答案\n\nint k = removeDuplicates(nums); // 调用\n\nassert k == expectedNums.length;\nfor (int i = 0; i < k; i++) {\n assert nums[i] == expectedNums[i];\n}\n\n
如果所有断言都通过,那么您的题解将被 通过。
\n\n\n\n
示例 1:
\n\n\n输入:nums = [1,1,2]\n输出:2, nums = [1,2,_]\n解释:函数应该返回新的长度\n\n2
,并且原数组 nums 的前两个元素被修改为1
,2
。
不需要考虑数组中超出新长度后面的元素。\n
示例 2:
\n\n\n输入:nums = [0,0,1,1,1,2,2,3,3,4]\n输出:5, nums = [0,1,2,3,4]\n解释:函数应该返回新的长度\n\n5
, 并且原数组 nums 的前五个元素被修改为0
,1
,2
,3
,4
。不需要考虑数组中超出新长度后面的元素。\n
\n\n
提示:
\n\n1 <= nums.length <= 3 * 104
-104 <= nums[i] <= 104
nums
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