The complement of an integer is the integer you get when you flip all the 0's to 1's and all the 1's to 0's in its binary representation.
5 is "101" in binary and its complement is "010" which is the integer 2.Given an integer num, return its complement.
\n
Example 1:
\n\n\nInput: num = 5\nOutput: 2\nExplanation: The binary representation of 5 is 101 (no leading zero bits), and its complement is 010. So you need to output 2.\n\n\n
Example 2:
\n\n\nInput: num = 1\nOutput: 0\nExplanation: The binary representation of 1 is 1 (no leading zero bits), and its complement is 0. So you need to output 0.\n\n\n
\n
Constraints:
\n\n1 <= num < 231\n
Note: This question is the same as 1009: https://leetcode.com/problems/complement-of-base-10-integer/
\n", "translatedTitle": "数字的补数", "translatedContent": "对整数的二进制表示取反（0 变 1 ，1 变 0）后，再转换为十进制表示，可以得到这个整数的补数。
5 的二进制表示是 \"101\" ，取反后得到 \"010\" ，再转回十进制表示得到补数 2 。给你一个整数 num ，输出它的补数。
\n\n
示例 1：
\n\n\n输入：num = 5\n输出：2\n解释：5 的二进制表示为 101（没有前导零位），其补数为 010。所以你需要输出 2 。\n\n\n
示例 2：
\n\n\n输入：num = 1\n输出：0\n解释：1 的二进制表示为 1（没有前导零位），其补数为 0。所以你需要输出 0 。\n\n\n
\n\n
提示：
\n\n1 <= num < 231\n\n
注意：本题与 1009 https://leetcode-cn.com/problems/complement-of-base-10-integer/ 相同
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