{ "data": { "question": { "questionId": "1674", "questionFrontendId": "1551", "categoryTitle": "Algorithms", "boundTopicId": 371621, "title": "Minimum Operations to Make Array Equal", "titleSlug": "minimum-operations-to-make-array-equal", "content": "

You have an array arr of length n where arr[i] = (2 * i) + 1 for all valid values of i (i.e., 0 <= i < n).

\n\n

In one operation, you can select two indices x and y where 0 <= x, y < n and subtract 1 from arr[x] and add 1 to arr[y] (i.e., perform arr[x] -=1 and arr[y] += 1). The goal is to make all the elements of the array equal. It is guaranteed that all the elements of the array can be made equal using some operations.

\n\n

Given an integer n, the length of the array, return the minimum number of operations needed to make all the elements of arr equal.

\n\n

 

\n

Example 1:

\n\n
\nInput: n = 3\nOutput: 2\nExplanation: arr = [1, 3, 5]\nFirst operation choose x = 2 and y = 0, this leads arr to be [2, 3, 4]\nIn the second operation choose x = 2 and y = 0 again, thus arr = [3, 3, 3].\n
\n\n

Example 2:

\n\n
\nInput: n = 6\nOutput: 9\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "使数组中所有元素相等的最小操作数", "translatedContent": "

存在一个长度为 n 的数组 arr ,其中 arr[i] = (2 * i) + 10 <= i < n )。

\n\n

一次操作中,你可以选出两个下标,记作 xy0 <= x, y < n )并使 arr[x] 减去 1arr[y] 加上 1 (即 arr[x] -=1 arr[y] += 1 )。最终的目标是使数组中的所有元素都 相等 。题目测试用例将会 保证 :在执行若干步操作后,数组中的所有元素最终可以全部相等。

\n\n

给你一个整数 n,即数组的长度。请你返回使数组 arr 中所有元素相等所需的 最小操作数

\n\n

 

\n\n

示例 1:

\n\n
输入:n = 3\n输出:2\n解释:arr = [1, 3, 5]\n第一次操作选出 x = 2 和 y = 0,使数组变为 [2, 3, 4]\n第二次操作继续选出 x = 2 和 y = 0,数组将会变成 [3, 3, 3]\n
\n\n

示例 2:

\n\n
输入:n = 6\n输出:9\n
\n\n

 

\n\n

提示:

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