You are given a binary string s that contains at least one '1'.
You have to rearrange the bits in such a way that the resulting binary number is the maximum odd binary number that can be created from this combination.
\n\nReturn a string representing the maximum odd binary number that can be created from the given combination.
\n\nNote that the resulting string can have leading zeros.
\n\n\n
Example 1:
\n\n\nInput: s = "010"\nOutput: "001"\nExplanation: Because there is just one '1', it must be in the last position. So the answer is "001".\n\n\n
Example 2:
\n\n\nInput: s = "0101"\nOutput: "1001"\nExplanation: One of the '1's must be in the last position. The maximum number that can be made with the remaining digits is "100". So the answer is "1001".\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 100s consists only of '0' and '1'.s contains at least one '1'.给你一个 二进制 字符串 s ，其中至少包含一个 '1' 。
你必须按某种方式 重新排列 字符串中的位，使得到的二进制数字是可以由该组合生成的 最大二进制奇数 。
\n\n以字符串形式，表示并返回可以由给定组合生成的最大二进制奇数。
\n\n注意 返回的结果字符串 可以 含前导零。
\n\n\n\n
示例 1：
\n\n\n输入：s = \"010\"\n输出：\"001\"\n解释：因为字符串 s 中仅有一个 '1' ，其必须出现在最后一位上。所以答案是 \"001\" 。\n\n\n
示例 2：
\n\n\n输入：s = \"0101\"\n输出：\"1001\"\n解释：其中一个 '1' 必须出现在最后一位上。而由剩下的数字可以生产的最大数字是 \"100\" 。所以答案是 \"1001\" 。\n\n\n
\n\n
提示：
\n\n1 <= s.length <= 100s 仅由 '0' 和 '1' 组成s 中至少包含一个 '1''1' in the least significant place."
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