Given an integer array nums, return the maximum difference between two successive elements in its sorted form. If the array contains less than two elements, return 0.
You must write an algorithm that runs in linear time and uses linear extra space.
\n\n\n
Example 1:
\n\n\nInput: nums = [3,6,9,1]\nOutput: 3\nExplanation: The sorted form of the array is [1,3,6,9], either (3,6) or (6,9) has the maximum difference 3.\n\n\n
Example 2:
\n\n\nInput: nums = [10]\nOutput: 0\nExplanation: The array contains less than 2 elements, therefore return 0.\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 1050 <= nums[i] <= 109给定一个无序的数组 nums，返回 数组在排序之后，相邻元素之间最大的差值 。如果数组元素个数小于 2，则返回 0 。
您必须编写一个在「线性时间」内运行并使用「线性额外空间」的算法。
\n\n\n\n
示例 1:
\n\n\n输入: nums = [3,6,9,1]\n输出: 3\n解释: 排序后的数组是 [1,3,6,9], 其中相邻元素 (3,6) 和 (6,9) 之间都存在最大差值 3。\n\n
示例 2:
\n\n\n输入: nums = [10]\n输出: 0\n解释: 数组元素个数小于 2，因此返回 0。\n\n
\n\n
提示:
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