Given a binary array nums, return the maximum number of consecutive 1's in the array.
\n
Example 1:
\n\n\nInput: nums = [1,1,0,1,1,1]\nOutput: 3\nExplanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.\n\n\n
Example 2:
\n\n\nInput: nums = [1,0,1,1,0,1]\nOutput: 2\n\n\n
\n
Constraints:
\n\n1 <= nums.length <= 105nums[i] is either 0 or 1.给定一个二进制数组 nums ， 计算其中最大连续 1 的个数。
\n\n
示例 1：
\n\n\n输入：nums = [1,1,0,1,1,1]\n输出：3\n解释：开头的两位和最后的三位都是连续 1 ，所以最大连续 1 的个数是 3.\n\n\n
示例 2:
\n\n\n输入：nums = [1,0,1,1,0,1]\n输出：2\n\n\n
\n\n
提示：
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"exampleTestcases": "[1,1,0,1,1,1]\n[1,0,1,1,0,1]",
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