You are given two strings s and pattern.
A string x is called almost equal to y if you can change at most one character in x to make it identical to y.
Return the smallest starting index of a substring in s that is almost equal to pattern. If no such index exists, return -1.
\n
Example 1:
\n\nInput: s = "abcdefg", pattern = "bcdffg"
\n\nOutput: 1
\n\nExplanation:
\n\nThe substring s[1..6] == "bcdefg" can be converted to "bcdffg" by changing s[4] to "f".
Example 2:
\n\nInput: s = "ababbababa", pattern = "bacaba"
\n\nOutput: 4
\n\nExplanation:
\n\nThe substring s[4..9] == "bababa" can be converted to "bacaba" by changing s[6] to "c".
Example 3:
\n\nInput: s = "abcd", pattern = "dba"
\n\nOutput: -1
\nExample 4:
\n\nInput: s = "dde", pattern = "d"
\n\nOutput: 0
\n\n
Constraints:
\n\n1 <= pattern.length < s.length <= 105s and pattern consist only of lowercase English letters.\nFollow-up: Could you solve the problem if at most
k consecutive characters can be changed?",
"translatedTitle": "第一个几乎相等子字符串的下标",
"translatedContent": "给你两个字符串 s 和 pattern 。
如果一个字符串 x 修改 至多 一个字符会变成 y ，那么我们称它与 y 几乎相等 。
请你返回 s 中下标 最小 的 子字符串 ，它与 pattern 几乎相等 。如果不存在，返回 -1 。
子字符串 是字符串中的一个 非空、连续的字符序列。
\n\n\n\n
示例 1：
\n\n输入：s = \"abcdefg\", pattern = \"bcdffg\"
\n\n输出：1
\n\n解释：
\n\n将子字符串 s[1..6] == \"bcdefg\" 中 s[4] 变为 \"f\" ，得到 \"bcdffg\" 。
示例 2：
\n\n输入：s = \"ababbababa\", pattern = \"bacaba\"
\n\n输出：4
\n\n解释：
\n\n将子字符串 s[4..9] == \"bababa\" 中 s[6] 变为 \"c\" ，得到 \"bacaba\" 。
示例 3：
\n\n输入：s = \"abcd\", pattern = \"dba\"
\n\n输出：-1
\n示例 4：
\n\n输入：s = \"dde\", pattern = \"d\"
\n\n输出：0
\n\n\n
提示：
\n\n1 <= pattern.length < s.length <= 105s 和 pattern 都只包含小写英文字母。\n进阶：如果题目变为 至多
k 个 连续 字符可以被修改，你可以想出解法吗？",
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"Consider a window of size pattern.length. If dp1[i] + i == i + pattern.length - 1 - dp2[i + pattern.length - 1], what does this signify?"
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}clang 19<\\/code> \\u91c7\\u7528\\u6700\\u65b0 C++ 23 \\u6807\\u51c6\\uff0c\\u5e76\\u4f7f\\u7528 GCC 14 \\u63d0\\u4f9b\\u7684 libstdc++<\\/code>\\u3002<\\/p>\\r\\n\\r\\n-O2<\\/code> \\u7ea7\\u4f18\\u5316\\uff0c\\u5e76\\u63d0\\u4f9b -gline-tables-only<\\/code> \\u53c2\\u6570\\u3002AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b out-of-bounds<\\/code> \\u548c use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\nOpenJDK 21<\\/code>\\u3002\\u4f7f\\u7528\\u7f16\\u8bd1\\u53c2\\u6570 --enable-preview --release 21<\\/code><\\/p>\\r\\n\\r\\nPython 2.7.18<\\/code><\\/p>\\r\\n\\r\\nGCC 14<\\/code>\\uff0c\\u91c7\\u7528 GNU11 \\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n-O2<\\/code> \\u7ea7\\u4f18\\u5316\\uff0c\\u5e76\\u63d0\\u4f9b -g1<\\/code> \\u53c2\\u6570\\u3002 AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b out-of-bounds<\\/code> \\u548c use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"Node.js 20.10.0<\\/code><\\/p>\\r\\n\\r\\n--harmony<\\/code> \\u6807\\u8bb0\\u6765\\u5f00\\u542f \\u65b0\\u7248ES6\\u7279\\u6027<\\/a>\\u3002<\\/p>\\r\\n\\r\\nRuby 3.2<\\/code> \\u6267\\u884c<\\/p>\\r\\n\\r\\nSwift 6.0<\\/code><\\/p>\\r\\n\\r\\nGo 1.23<\\/code><\\/p>\\r\\n\\r\\nPython 3.11<\\/code><\\/p>\\r\\n\\r\\nScala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\nrust 1.79.0<\\/code><\\/p>\\r\\n\\r\\nPHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n-O2 --disable-reflection<\\/code><\\/p>\\r\\n\\r\\n