Given an integer array nums of length n where all the integers of nums are in the range [1, n] and each integer appears at most twice, return an array of all the integers that appears twice.
You must write an algorithm that runs in O(n) time and uses only constant auxiliary space, excluding the space needed to store the output
\n
Example 1:
\nInput: nums = [4,3,2,7,8,2,3,1]\nOutput: [2,3]\n
Example 2:
\nInput: nums = [1,1,2]\nOutput: [1]\n
Example 3:
\nInput: nums = [1]\nOutput: []\n\n
\n
Constraints:
\n\nn == nums.length1 <= n <= 1051 <= nums[i] <= nnums appears once or twice.给你一个长度为 n 的整数数组 nums ，其中 nums 的所有整数都在范围 [1, n] 内，且每个整数出现 最多两次 。请你找出所有出现 两次 的整数，并以数组形式返回。
你必须设计并实现一个时间复杂度为 O(n) 且仅使用常量额外空间（不包括存储输出所需的空间）的算法解决此问题。
\n\n
示例 1：
\n\n\n输入：nums = [4,3,2,7,8,2,3,1]\n输出：[2,3]\n\n\n
示例 2：
\n\n\n输入：nums = [1,1,2]\n输出：[1]\n\n\n
示例 3：
\n\n\n输入：nums = [1]\n输出：[]\n\n\n
\n\n
提示：
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