{ "data": { "question": { "questionId": "1934", "questionFrontendId": "1807", "categoryTitle": "Algorithms", "boundTopicId": 678957, "title": "Evaluate the Bracket Pairs of a String", "titleSlug": "evaluate-the-bracket-pairs-of-a-string", "content": "
You are given a string s
that contains some bracket pairs, with each pair containing a non-empty key.
"(name)is(age)yearsold"
, there are two bracket pairs that contain the keys "name"
and "age"
.You know the values of a wide range of keys. This is represented by a 2D string array knowledge
where each knowledge[i] = [keyi, valuei]
indicates that key keyi
has a value of valuei
.
You are tasked to evaluate all of the bracket pairs. When you evaluate a bracket pair that contains some key keyi
, you will:
keyi
and the bracket pair with the key's corresponding valuei
.keyi
and the bracket pair with a question mark "?"
(without the quotation marks).Each key will appear at most once in your knowledge
. There will not be any nested brackets in s
.
Return the resulting string after evaluating all of the bracket pairs.
\n\n\n
Example 1:
\n\n\nInput: s = "(name)is(age)yearsold", knowledge = [["name","bob"],["age","two"]]\nOutput: "bobistwoyearsold"\nExplanation:\nThe key "name" has a value of "bob", so replace "(name)" with "bob".\nThe key "age" has a value of "two", so replace "(age)" with "two".\n\n\n
Example 2:
\n\n\nInput: s = "hi(name)", knowledge = [["a","b"]]\nOutput: "hi?"\nExplanation: As you do not know the value of the key "name", replace "(name)" with "?".\n\n\n
Example 3:
\n\n\nInput: s = "(a)(a)(a)aaa", knowledge = [["a","yes"]]\nOutput: "yesyesyesaaa"\nExplanation: The same key can appear multiple times.\nThe key "a" has a value of "yes", so replace all occurrences of "(a)" with "yes".\nNotice that the "a"s not in a bracket pair are not evaluated.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 105
0 <= knowledge.length <= 105
knowledge[i].length == 2
1 <= keyi.length, valuei.length <= 10
s
consists of lowercase English letters and round brackets '('
and ')'
.'('
in s
will have a corresponding close bracket ')'
.s
will be non-empty.s
.keyi
and valuei
consist of lowercase English letters.keyi
in knowledge
is unique.给你一个字符串 s
,它包含一些括号对,每个括号中包含一个 非空 的键。
\"(name)is(age)yearsold\"
中,有 两个 括号对,分别包含键 \"name\"
和 \"age\"
。你知道许多键对应的值,这些关系由二维字符串数组 knowledge
表示,其中 knowledge[i] = [keyi, valuei]
,表示键 keyi
对应的值为 valuei
。
你需要替换 所有 的括号对。当你替换一个括号对,且它包含的键为 keyi
时,你需要:
keyi
和括号用对应的值 valuei
替换。knowledge
中无法得知某个键对应的值,你需要将 keyi
和括号用问号 \"?\"
替换(不需要引号)。knowledge
中每个键最多只会出现一次。s
中不会有嵌套的括号。
请你返回替换 所有 括号对后的结果字符串。
\n\n\n\n
示例 1:
\n\n\n输入:s = \"(name)is(age)yearsold\", knowledge = [[\"name\",\"bob\"],[\"age\",\"two\"]]\n输出:\"bobistwoyearsold\"\n解释:\n键 \"name\" 对应的值为 \"bob\" ,所以将 \"(name)\" 替换为 \"bob\" 。\n键 \"age\" 对应的值为 \"two\" ,所以将 \"(age)\" 替换为 \"two\" 。\n\n\n
示例 2:
\n\n\n输入:s = \"hi(name)\", knowledge = [[\"a\",\"b\"]]\n输出:\"hi?\"\n解释:由于不知道键 \"name\" 对应的值,所以用 \"?\" 替换 \"(name)\" 。\n\n\n
示例 3:
\n\n\n输入:s = \"(a)(a)(a)aaa\", knowledge = [[\"a\",\"yes\"]]\n输出:\"yesyesyesaaa\"\n解释:相同的键在 s 中可能会出现多次。\n键 \"a\" 对应的值为 \"yes\" ,所以将所有的 \"(a)\" 替换为 \"yes\" 。\n注意,不在括号里的 \"a\" 不需要被替换。\n\n\n
\n\n
提示:
\n\n1 <= s.length <= 105
0 <= knowledge.length <= 105
knowledge[i].length == 2
1 <= keyi.length, valuei.length <= 10
s
只包含小写英文字母和圆括号 '('
和 ')'
。s
中每一个左圆括号 '('
都有对应的右圆括号 ')'
。s
中每对括号内的键都不会为空。s
中不会有嵌套括号对。keyi
和 valuei
只包含小写英文字母。knowledge
中的 keyi
不会重复。\\u7248\\u672c\\uff1a \\u7f16\\u8bd1\\u65f6\\uff0c\\u5c06\\u4f1a\\u91c7\\u7528 \\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\"],\"java\":[\"Java\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u88ab\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n \\u5305\\u542b Pair \\u7c7b: https:\\/\\/docs.oracle.com\\/javase\\/8\\/javafx\\/api\\/javafx\\/util\\/Pair.html <\\/p>\"],\"python\":[\"Python\",\" \\u7248\\u672c\\uff1a \\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982\\uff1aarray<\\/a>, bisect<\\/a>, 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With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\" TypeScript 5.1.6<\\/p>\\r\\n\\r\\n Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\" Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n \\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n \\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 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libstdc++<\\/code>\\u3002<\\/p>\\r\\n\\r\\n
-O2<\\/code> \\u7ea7\\u4f18\\u5316\\uff0c\\u5e76\\u63d0\\u4f9b
-gline-tables-only<\\/code> \\u53c2\\u6570\\u3002AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b
out-of-bounds<\\/code> \\u548c
use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
OpenJDK 21<\\/code>\\u3002\\u4f7f\\u7528\\u7f16\\u8bd1\\u53c2\\u6570
--enable-preview --release 21<\\/code><\\/p>\\r\\n\\r\\n
Python 2.7.18<\\/code><\\/p>\\r\\n\\r\\n
GCC 14<\\/code>\\uff0c\\u91c7\\u7528 GNU11 \\u6807\\u51c6\\u3002<\\/p>\\r\\n\\r\\n
-O2<\\/code> \\u7ea7\\u4f18\\u5316\\uff0c\\u5e76\\u63d0\\u4f9b
-g1<\\/code> \\u53c2\\u6570\\u3002 AddressSanitizer<\\/a> \\u4e5f\\u88ab\\u5f00\\u542f\\u6765\\u68c0\\u6d4b
out-of-bounds<\\/code> \\u548c
use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\\r\\n\\r\\n
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\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n<\\/pre>\\r\\n<\\/p>\"],\"csharp\":[\"C#\",\"
Node.js 20.10.0<\\/code><\\/p>\\r\\n\\r\\n
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Ruby 3.2<\\/code> \\u6267\\u884c<\\/p>\\r\\n\\r\\n
Swift 6.0<\\/code><\\/p>\\r\\n\\r\\n
Go 1.23<\\/code><\\/p>\\r\\n\\r\\n
Python 3.11<\\/code><\\/p>\\r\\n\\r\\n
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Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n
rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n
PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n
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