{ "data": { "question": { "questionId": "1934", "questionFrontendId": "1807", "categoryTitle": "Algorithms", "boundTopicId": 678957, "title": "Evaluate the Bracket Pairs of a String", "titleSlug": "evaluate-the-bracket-pairs-of-a-string", "content": "

You are given a string s that contains some bracket pairs, with each pair containing a non-empty key.

\n\n\n\n

You know the values of a wide range of keys. This is represented by a 2D string array knowledge where each knowledge[i] = [keyi, valuei] indicates that key keyi has a value of valuei.

\n\n

You are tasked to evaluate all of the bracket pairs. When you evaluate a bracket pair that contains some key keyi, you will:

\n\n\n\n

Each key will appear at most once in your knowledge. There will not be any nested brackets in s.

\n\n

Return the resulting string after evaluating all of the bracket pairs.

\n\n

 

\n

Example 1:

\n\n
\nInput: s = "(name)is(age)yearsold", knowledge = [["name","bob"],["age","two"]]\nOutput: "bobistwoyearsold"\nExplanation:\nThe key "name" has a value of "bob", so replace "(name)" with "bob".\nThe key "age" has a value of "two", so replace "(age)" with "two".\n
\n\n

Example 2:

\n\n
\nInput: s = "hi(name)", knowledge = [["a","b"]]\nOutput: "hi?"\nExplanation: As you do not know the value of the key "name", replace "(name)" with "?".\n
\n\n

Example 3:

\n\n
\nInput: s = "(a)(a)(a)aaa", knowledge = [["a","yes"]]\nOutput: "yesyesyesaaa"\nExplanation: The same key can appear multiple times.\nThe key "a" has a value of "yes", so replace all occurrences of "(a)" with "yes".\nNotice that the "a"s not in a bracket pair are not evaluated.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "替换字符串中的括号内容", "translatedContent": "

给你一个字符串 s ,它包含一些括号对,每个括号中包含一个 非空 的键。

\n\n\n\n

你知道许多键对应的值,这些关系由二维字符串数组 knowledge 表示,其中 knowledge[i] = [keyi, valuei] ,表示键 keyi 对应的值为 valuei 

\n\n

你需要替换 所有 的括号对。当你替换一个括号对,且它包含的键为 keyi 时,你需要:

\n\n\n\n

knowledge 中每个键最多只会出现一次。s 中不会有嵌套的括号。

\n\n

请你返回替换 所有 括号对后的结果字符串。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:s = \"(name)is(age)yearsold\", knowledge = [[\"name\",\"bob\"],[\"age\",\"two\"]]\n输出:\"bobistwoyearsold\"\n解释:\n键 \"name\" 对应的值为 \"bob\" ,所以将 \"(name)\" 替换为 \"bob\" 。\n键 \"age\" 对应的值为 \"two\" ,所以将 \"(age)\" 替换为 \"two\" 。\n
\n\n

示例 2:

\n\n
\n输入:s = \"hi(name)\", knowledge = [[\"a\",\"b\"]]\n输出:\"hi?\"\n解释:由于不知道键 \"name\" 对应的值,所以用 \"?\" 替换 \"(name)\" 。\n
\n\n

示例 3:

\n\n
\n输入:s = \"(a)(a)(a)aaa\", knowledge = [[\"a\",\"yes\"]]\n输出:\"yesyesyesaaa\"\n解释:相同的键在 s 中可能会出现多次。\n键 \"a\" 对应的值为 \"yes\" ,所以将所有的 \"(a)\" 替换为 \"yes\" 。\n注意,不在括号里的 \"a\" 不需要被替换。\n
\n\n

 

\n\n

提示:

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