{ "data": { "question": { "questionId": "91", "questionFrontendId": "91", "categoryTitle": "Algorithms", "boundTopicId": 1174, "title": "Decode Ways", "titleSlug": "decode-ways", "content": "

You have intercepted a secret message encoded as a string of numbers. The message is decoded via the following mapping:

\n\n

"1" -> 'A'
\n"2" -> 'B'
\n...
\n"25" -> 'Y'
\n"26" -> 'Z'

\n\n

However, while decoding the message, you realize that there are many different ways you can decode the message because some codes are contained in other codes ("2" and "5" vs "25").

\n\n

For example, "11106" can be decoded into:

\n\n\n\n

Note: there may be strings that are impossible to decode.
\n
\nGiven a string s containing only digits, return the number of ways to decode it. If the entire string cannot be decoded in any valid way, return 0.

\n\n

The test cases are generated so that the answer fits in a 32-bit integer.

\n\n

 

\n

Example 1:

\n\n
\n

Input: s = "12"

\n\n

Output: 2

\n\n

Explanation:

\n\n

"12" could be decoded as "AB" (1 2) or "L" (12).

\n
\n\n

Example 2:

\n\n
\n

Input: s = "226"

\n\n

Output: 3

\n\n

Explanation:

\n\n

"226" could be decoded as "BZ" (2 26), "VF" (22 6), or "BBF" (2 2 6).

\n
\n\n

Example 3:

\n\n
\n

Input: s = "06"

\n\n

Output: 0

\n\n

Explanation:

\n\n

"06" cannot be mapped to "F" because of the leading zero ("6" is different from "06"). In this case, the string is not a valid encoding, so return 0.

\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "解码方法", "translatedContent": "

一条包含字母 A-Z 的消息通过以下映射进行了 编码

\n\n

\"1\" -> 'A'
\n\"2\" -> 'B'
\n...
\n\"25\" -> 'Y'
\n\"26\" -> 'Z'

\n\n

然而,在 解码 已编码的消息时,你意识到有许多不同的方式来解码,因为有些编码被包含在其它编码当中(\"2\"\"5\"\"25\")。

\n\n

例如,\"11106\" 可以映射为:

\n\n\n\n

注意,可能存在无法解码的字符串。

\n\n

给你一个只含数字的 非空 字符串 s ,请计算并返回 解码 方法的 总数 。如果没有合法的方式解码整个字符串,返回 0

\n\n

题目数据保证答案肯定是一个 32 位 的整数。

\n\n

 

\n\n

示例 1:

\n\n
\n输入:s = \"12\"\n输出:2\n解释:它可以解码为 \"AB\"(1 2)或者 \"L\"(12)。\n
\n\n

示例 2:

\n\n
\n输入:s = \"226\"\n输出:3\n解释:它可以解码为 \"BZ\" (2 26), \"VF\" (22 6), 或者 \"BBF\" (2 2 6) 。\n
\n\n

示例 3:

\n\n
\n输入:s = \"06\"\n输出:0\n解释:\"06\" 无法映射到 \"F\" ,因为存在前导零(\"6\" 和 \"06\" 并不等价)。\n
\n\n

 

\n\n

提示:

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