{ "data": { "question": { "questionId": "2608", "questionFrontendId": "2520", "categoryTitle": "Algorithms", "boundTopicId": 2035769, "title": "Count the Digits That Divide a Number", "titleSlug": "count-the-digits-that-divide-a-number", "content": "

Given an integer num, return the number of digits in num that divide num.

\n\n

An integer val divides nums if nums % val == 0.

\n\n

 

\n

Example 1:

\n\n
\nInput: num = 7\nOutput: 1\nExplanation: 7 divides itself, hence the answer is 1.\n
\n\n

Example 2:

\n\n
\nInput: num = 121\nOutput: 2\nExplanation: 121 is divisible by 1, but not 2. Since 1 occurs twice as a digit, we return 2.\n
\n\n

Example 3:

\n\n
\nInput: num = 1248\nOutput: 4\nExplanation: 1248 is divisible by all of its digits, hence the answer is 4.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "统计能整除数字的位数", "translatedContent": "

给你一个整数 num ,返回 num 中能整除 num 的数位的数目。

\n\n

如果满足 nums % val == 0 ,则认为整数 val 可以整除 nums

\n\n

 

\n\n

示例 1:

\n\n
输入:num = 7\n输出:1\n解释:7 被自己整除,因此答案是 1 。\n
\n\n

示例 2:

\n\n
输入:num = 121\n输出:2\n解释:121 可以被 1 整除,但无法被 2 整除。由于 1 出现两次,所以返回 2 。\n
\n\n

示例 3:

\n\n
输入:num = 1248\n输出:4\n解释:1248 可以被它每一位上的数字整除,因此答案是 4 。\n
\n\n

 

\n\n

提示:

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