You are given a string s and a positive integer k.
Let vowels and consonants be the number of vowels and consonants in a string.
A string is beautiful if:
\n\nvowels == consonants.(vowels * consonants) % k == 0, in other terms the multiplication of vowels and consonants is divisible by k.Return the number of non-empty beautiful substrings in the given string s.
A substring is a contiguous sequence of characters in a string.
\n\nVowel letters in English are 'a', 'e', 'i', 'o', and 'u'.
Consonant letters in English are every letter except vowels.
\n\n\n
Example 1:
\n\n\nInput: s = "baeyh", k = 2\nOutput: 2\nExplanation: There are 2 beautiful substrings in the given string.\n- Substring "baeyh", vowels = 2 (["a",e"]), consonants = 2 (["y","h"]).\nYou can see that string "aeyh" is beautiful as vowels == consonants and vowels * consonants % k == 0.\n- Substring "baeyh", vowels = 2 (["a",e"]), consonants = 2 (["b","y"]).\nYou can see that string "baey" is beautiful as vowels == consonants and vowels * consonants % k == 0.\nIt can be shown that there are only 2 beautiful substrings in the given string.\n\n\n
Example 2:
\n\n\nInput: s = "abba", k = 1\nOutput: 3\nExplanation: There are 3 beautiful substrings in the given string.\n- Substring "abba", vowels = 1 (["a"]), consonants = 1 (["b"]).\n- Substring "abba", vowels = 1 (["a"]), consonants = 1 (["b"]).\n- Substring "abba", vowels = 2 (["a","a"]), consonants = 2 (["b","b"]).\nIt can be shown that there are only 3 beautiful substrings in the given string.\n\n\n
Example 3:
\n\n\nInput: s = "bcdf", k = 1\nOutput: 0\nExplanation: There are no beautiful substrings in the given string.\n\n\n
\n
Constraints:
\n\n1 <= s.length <= 5 * 1041 <= k <= 1000s consists of only English lowercase letters.给你一个字符串 s 和一个正整数 k 。
用 vowels 和 consonants 分别表示字符串中元音字母和辅音字母的数量。
如果某个字符串满足以下条件，则称其为 美丽字符串 ：
\n\nvowels == consonants，即元音字母和辅音字母的数量相等。(vowels * consonants) % k == 0，即元音字母和辅音字母的数量的乘积能被 k 整除。返回字符串 s 中 非空美丽子字符串 的数量。
子字符串是字符串中的一个连续字符序列。
\n\n英语中的 元音字母 为 'a'、'e'、'i'、'o' 和 'u' 。
英语中的 辅音字母 为除了元音字母之外的所有字母。
\n\n\n\n
示例 1：
\n\n\n输入：s = \"baeyh\", k = 2\n输出：2\n解释：字符串 s 中有 2 个美丽子字符串。\n- 子字符串 \"baeyh\"，vowels = 2（[\"a\",\"e\"]），consonants = 2（[\"y\",\"h\"]）。\n可以看出字符串 \"aeyh\" 是美丽字符串，因为 vowels == consonants 且 vowels * consonants % k == 0 。\n- 子字符串 \"baeyh\"，vowels = 2（[\"a\",\"e\"]），consonants = 2（[\"b\",\"y\"]）。\n可以看出字符串 \"baey\" 是美丽字符串，因为 vowels == consonants 且 vowels * consonants % k == 0 。\n可以证明字符串 s 中只有 2 个美丽子字符串。\n\n\n
示例 2：
\n\n\n输入：s = \"abba\", k = 1\n输出：3\n解释：字符串 s 中有 3 个美丽子字符串。\n- 子字符串 \"abba\"，vowels = 1（[\"a\"]），consonants = 1（[\"b\"]）。\n- 子字符串 \"abba\"，vowels = 1（[\"a\"]），consonants = 1（[\"b\"]）。\n- 子字符串 \"abba\"，vowels = 2（[\"a\",\"a\"]），consonants = 2（[\"b\",\"b\"]）。\n可以证明字符串 s 中只有 3 个美丽子字符串。\n\n\n
示例 3：
\n\n\n输入：s = \"bcdf\", k = 1\n输出：0\n解释：字符串 s 中没有美丽子字符串。\n\n\n
\n\n
提示：
\n\n1 <= s.length <= 5 * 1041 <= k <= 1000s 仅由小写英文字母组成。k find all the x integers such that x^2 % k == 0. Notice, that there aren’t many such candidates.",
"We can iterate over all such x values and count the number of substrings such that vowels == consonants == x.",
"This can be done with prefix sums and hash map."
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