{ "data": { "question": { "questionId": "925", "questionFrontendId": "889", "categoryTitle": "Algorithms", "boundTopicId": 1681, "title": "Construct Binary Tree from Preorder and Postorder Traversal", "titleSlug": "construct-binary-tree-from-preorder-and-postorder-traversal", "content": "
Given two integer arrays, preorder
and postorder
where preorder
is the preorder traversal of a binary tree of distinct values and postorder
is the postorder traversal of the same tree, reconstruct and return the binary tree.
If there exist multiple answers, you can return any of them.
\n\n\n
Example 1:
\n\nInput: preorder = [1,2,4,5,3,6,7], postorder = [4,5,2,6,7,3,1]\nOutput: [1,2,3,4,5,6,7]\n\n\n
Example 2:
\n\n\nInput: preorder = [1], postorder = [1]\nOutput: [1]\n\n\n
\n
Constraints:
\n\n1 <= preorder.length <= 30
1 <= preorder[i] <= preorder.length
preorder
are unique.postorder.length == preorder.length
1 <= postorder[i] <= postorder.length
postorder
are unique.preorder
and postorder
are the preorder traversal and postorder traversal of the same binary tree.给定两个整数数组,preorder
和 postorder
,其中 preorder
是一个具有 无重复 值的二叉树的前序遍历,postorder
是同一棵树的后序遍历,重构并返回二叉树。
如果存在多个答案,您可以返回其中 任何 一个。
\n\n\n\n
示例 1:
\n\n\n输入:preorder = [1,2,4,5,3,6,7], postorder = [4,5,2,6,7,3,1]\n输出:[1,2,3,4,5,6,7]\n\n\n
示例 2:
\n\n\n输入: preorder = [1], postorder = [1]\n输出: [1]\n\n\n
\n\n
提示:
\n\n1 <= preorder.length <= 30
1 <= preorder[i] <= preorder.length
preorder
中所有值都 不同postorder.length == preorder.length
1 <= postorder[i] <= postorder.length
postorder
中所有值都 不同preorder
和 postorder
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