{ "data": { "question": { "questionId": "2567", "questionFrontendId": "2476", "categoryTitle": "Algorithms", "boundTopicId": 1974250, "title": "Closest Nodes Queries in a Binary Search Tree", "titleSlug": "closest-nodes-queries-in-a-binary-search-tree", "content": "
You are given the root
of a binary search tree and an array queries
of size n
consisting of positive integers.
Find a 2D array answer
of size n
where answer[i] = [mini, maxi]
:
mini
is the largest value in the tree that is smaller than or equal to queries[i]
. If a such value does not exist, add -1
instead.maxi
is the smallest value in the tree that is greater than or equal to queries[i]
. If a such value does not exist, add -1
instead.Return the array answer
.
\n
Example 1:
\n\nInput: root = [6,2,13,1,4,9,15,null,null,null,null,null,null,14], queries = [2,5,16]\nOutput: [[2,2],[4,6],[15,-1]]\nExplanation: We answer the queries in the following way:\n- The largest number that is smaller or equal than 2 in the tree is 2, and the smallest number that is greater or equal than 2 is still 2. So the answer for the first query is [2,2].\n- The largest number that is smaller or equal than 5 in the tree is 4, and the smallest number that is greater or equal than 5 is 6. So the answer for the second query is [4,6].\n- The largest number that is smaller or equal than 16 in the tree is 15, and the smallest number that is greater or equal than 16 does not exist. So the answer for the third query is [15,-1].\n\n\n
Example 2:
\n\nInput: root = [4,null,9], queries = [3]\nOutput: [[-1,4]]\nExplanation: The largest number that is smaller or equal to 3 in the tree does not exist, and the smallest number that is greater or equal to 3 is 4. So the answer for the query is [-1,4].\n\n\n
\n
Constraints:
\n\n[2, 105]
.1 <= Node.val <= 106
n == queries.length
1 <= n <= 105
1 <= queries[i] <= 106
给你一个 二叉搜索树 的根节点 root
,和一个由正整数组成、长度为 n
的数组 queries
。
请你找出一个长度为 n
的 二维 答案数组 answer
,其中 answer[i] = [mini, maxi]
:
mini
是树中小于等于 queries[i]
的 最大值 。如果不存在这样的值,则使用 -1
代替。maxi
是树中大于等于 queries[i]
的 最小值 。如果不存在这样的值,则使用 -1
代替。返回数组 answer
。
\n\n
示例 1 :
\n\n\n输入:root = [6,2,13,1,4,9,15,null,null,null,null,null,null,14], queries = [2,5,16]\n输出:[[2,2],[4,6],[15,-1]]\n解释:按下面的描述找出并返回查询的答案:\n- 树中小于等于 2 的最大值是 2 ,且大于等于 2 的最小值也是 2 。所以第一个查询的答案是 [2,2] 。\n- 树中小于等于 5 的最大值是 4 ,且大于等于 5 的最小值是 6 。所以第二个查询的答案是 [4,6] 。\n- 树中小于等于 16 的最大值是 15 ,且大于等于 16 的最小值不存在。所以第三个查询的答案是 [15,-1] 。\n\n\n
示例 2 :
\n\n\n输入:root = [4,null,9], queries = [3]\n输出:[[-1,4]]\n解释:树中不存在小于等于 3 的最大值,且大于等于 3 的最小值是 4 。所以查询的答案是 [-1,4] 。\n\n\n
\n\n
提示:
\n\n[2, 105]
内1 <= Node.val <= 106
n == queries.length
1 <= n <= 105
1 <= queries[i] <= 106
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