You are given two strings s1 and s2, both of length 4, consisting of lowercase English letters.
You can apply the following operation on any of the two strings any number of times:
\n\ni and j such that j - i = 2, then swap the two characters at those indices in the string.Return true if you can make the strings s1 and s2 equal, and false otherwise.
\n
Example 1:
\n\n\nInput: s1 = "abcd", s2 = "cdab"\nOutput: true\nExplanation: We can do the following operations on s1:\n- Choose the indices i = 0, j = 2. The resulting string is s1 = "cbad".\n- Choose the indices i = 1, j = 3. The resulting string is s1 = "cdab" = s2.\n\n\n
Example 2:
\n\n\nInput: s1 = "abcd", s2 = "dacb"\nOutput: false\nExplanation: It is not possible to make the two strings equal.\n\n\n
\n
Constraints:
\n\ns1.length == s2.length == 4s1 and s2 consist only of lowercase English letters.给你两个字符串 s1 和 s2 ，两个字符串的长度都为 4 ，且只包含 小写 英文字母。
你可以对两个字符串中的 任意一个 执行以下操作 任意 次：
\n\ni 和 j 且满足 j - i = 2 ，然后 交换 这个字符串中两个下标对应的字符。如果你可以让字符串 s1 和 s2 相等，那么返回 true ，否则返回 false 。
\n\n
示例 1：
\n\n\n输入：s1 = \"abcd\", s2 = \"cdab\"\n输出：true\n解释： 我们可以对 s1 执行以下操作：\n- 选择下标 i = 0 ，j = 2 ，得到字符串 s1 = \"cbad\" 。\n- 选择下标 i = 1 ，j = 3 ，得到字符串 s1 = \"cdab\" = s2 。\n\n\n
示例 2：
\n\n\n输入：s1 = \"abcd\", s2 = \"dacb\"\n输出：false\n解释：无法让两个字符串相等。\n\n\n
\n\n
提示：
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"style": "LEETCODE",
"exampleTestcases": "\"abcd\"\n\"cdab\"\n\"abcd\"\n\"dacb\"",
"__typename": "QuestionNode"
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