{ "data": { "question": { "questionId": "2653", "questionFrontendId": "2510", "categoryTitle": "Algorithms", "boundTopicId": 2028770, "title": "Check if There is a Path With Equal Number of 0's And 1's", "titleSlug": "check-if-there-is-a-path-with-equal-number-of-0s-and-1s", "content": null, "translatedTitle": "检查是否有路径经过相同数量的 0 和 1", "translatedContent": null, "isPaidOnly": true, "difficulty": "Medium", "likes": 3, "dislikes": 0, "isLiked": null, "similarQuestions": "[{\"title\": \"Minimum Path Sum\", \"titleSlug\": \"minimum-path-sum\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u6700\\u5c0f\\u8def\\u5f84\\u548c\", \"isPaidOnly\": false}, {\"title\": \"Dungeon Game\", \"titleSlug\": \"dungeon-game\", \"difficulty\": \"Hard\", \"translatedTitle\": \"\\u5730\\u4e0b\\u57ce\\u6e38\\u620f\", \"isPaidOnly\": false}, {\"title\": \"Minimum Cost Homecoming of a Robot in a Grid\", \"titleSlug\": \"minimum-cost-homecoming-of-a-robot-in-a-grid\", \"difficulty\": \"Medium\", \"translatedTitle\": \"\\u7f51\\u683c\\u56fe\\u4e2d\\u673a\\u5668\\u4eba\\u56de\\u5bb6\\u7684\\u6700\\u5c0f\\u4ee3\\u4ef7\", \"isPaidOnly\": false}, {\"title\": \"Paths in Matrix Whose Sum Is Divisible by K\", \"titleSlug\": \"paths-in-matrix-whose-sum-is-divisible-by-k\", \"difficulty\": \"Hard\", \"translatedTitle\": \"\\u77e9\\u9635\\u4e2d\\u548c\\u80fd\\u88ab K \\u6574\\u9664\\u7684\\u8def\\u5f84\", \"isPaidOnly\": false}]", "contributors": [], "langToValidPlayground": null, "topicTags": [ { "name": "Array", "slug": "array", "translatedName": "数组", "__typename": "TopicTagNode" }, { "name": "Dynamic Programming", "slug": "dynamic-programming", "translatedName": "动态规划", "__typename": "TopicTagNode" }, { "name": "Matrix", "slug": "matrix", "translatedName": "矩阵", "__typename": "TopicTagNode" } ], "companyTagStats": null, "codeSnippets": null, "stats": "{\"totalAccepted\": \"674\", \"totalSubmission\": \"1K\", \"totalAcceptedRaw\": 674, \"totalSubmissionRaw\": 1049, \"acRate\": \"64.3%\"}", "hints": [ "Can you use dynamic programming to solve the problem?", "Let dp[i][j][diff] be true if there is a path from the cell (i, j) to (m - 1, n - 1) such that the difference between the number of 0’s and the number of 1’s that we visited so far is diff, or false otherwise. The answer to the problem will be dp[0][0][0]. How do you compute this dp?" ], "solution": null, "status": null, "sampleTestCase": "[[0,1,0,0],[0,1,0,0],[1,0,1,0]]", "metaData": "{\n \"name\": \"isThereAPath\",\n \"params\": [\n {\n \"name\": \"grid\",\n \"type\": \"integer[][]\"\n }\n ],\n \"return\": {\n \"type\": \"boolean\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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