<p>Given a <strong>0-indexed</strong> integer array <code>nums</code>, return <code>true</code> <em>if it can be made <strong>strictly increasing</strong> after removing <strong>exactly one</strong> element, or </em><code>false</code><em> otherwise. If the array is already strictly increasing, return </em><code>true</code>.</p> <p>The array <code>nums</code> is <strong>strictly increasing</strong> if <code>nums[i - 1] < nums[i]</code> for each index <code>(1 <= i < nums.length).</code></p> <p> </p> <p><strong>Example 1:</strong></p> <pre> <strong>Input:</strong> nums = [1,2,<u>10</u>,5,7] <strong>Output:</strong> true <strong>Explanation:</strong> By removing 10 at index 2 from nums, it becomes [1,2,5,7]. [1,2,5,7] is strictly increasing, so return true. </pre> <p><strong>Example 2:</strong></p> <pre> <strong>Input:</strong> nums = [2,3,1,2] <strong>Output:</strong> false <strong>Explanation:</strong> [3,1,2] is the result of removing the element at index 0. [2,1,2] is the result of removing the element at index 1. [2,3,2] is the result of removing the element at index 2. [2,3,1] is the result of removing the element at index 3. No resulting array is strictly increasing, so return false.</pre> <p><strong>Example 3:</strong></p> <pre> <strong>Input:</strong> nums = [1,1,1] <strong>Output:</strong> false <strong>Explanation:</strong> The result of removing any element is [1,1]. [1,1] is not strictly increasing, so return false. </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>2 <= nums.length <= 1000</code></li> <li><code>1 <= nums[i] <= 1000</code></li> </ul>