<p>You are given a string <code>word</code> that consists of digits and lowercase English letters.</p> <p>You will replace every non-digit character with a space. For example, <code>"a123bc34d8ef34"</code> will become <code>" 123 34 8 34"</code>. Notice that you are left with some integers that are separated by at least one space: <code>"123"</code>, <code>"34"</code>, <code>"8"</code>, and <code>"34"</code>.</p> <p>Return <em>the number of <strong>different</strong> integers after performing the replacement operations on </em><code>word</code>.</p> <p>Two integers are considered different if their decimal representations <strong>without any leading zeros</strong> are different.</p> <p> </p> <p><strong>Example 1:</strong></p> <pre> <strong>Input:</strong> word = "a<u>123</u>bc<u>34</u>d<u>8</u>ef<u>34</u>" <strong>Output:</strong> 3 <strong>Explanation: </strong>The three different integers are "123", "34", and "8". Notice that "34" is only counted once. </pre> <p><strong>Example 2:</strong></p> <pre> <strong>Input:</strong> word = "leet<u>1234</u>code<u>234</u>" <strong>Output:</strong> 2 </pre> <p><strong>Example 3:</strong></p> <pre> <strong>Input:</strong> word = "a<u>1</u>b<u>01</u>c<u>001</u>" <strong>Output:</strong> 1 <strong>Explanation: </strong>The three integers "1", "01", and "001" all represent the same integer because the leading zeros are ignored when comparing their decimal values. </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= word.length <= 1000</code></li> <li><code>word</code> consists of digits and lowercase English letters.</li> </ul>