<p>You are given a <strong>0-indexed</strong> array <code>nums</code> and an integer <code>target</code>.</p> <p>A <strong>0-indexed</strong> array <code>infinite_nums</code> is generated by infinitely appending the elements of <code>nums</code> to itself.</p> <p>Return <em>the length of the <strong>shortest</strong> subarray of the array </em><code>infinite_nums</code><em> with a sum equal to </em><code>target</code><em>.</em> If there is no such subarray return <code>-1</code>.</p> <p> </p> <p><strong class="example">Example 1:</strong></p> <pre> <strong>Input:</strong> nums = [1,2,3], target = 5 <strong>Output:</strong> 2 <strong>Explanation:</strong> In this example infinite_nums = [1,2,3,1,2,3,1,2,...]. The subarray in the range [1,2], has the sum equal to target = 5 and length = 2. It can be proven that 2 is the shortest length of a subarray with sum equal to target = 5. </pre> <p><strong class="example">Example 2:</strong></p> <pre> <strong>Input:</strong> nums = [1,1,1,2,3], target = 4 <strong>Output:</strong> 2 <strong>Explanation:</strong> In this example infinite_nums = [1,1,1,2,3,1,1,1,2,3,1,1,...]. The subarray in the range [4,5], has the sum equal to target = 4 and length = 2. It can be proven that 2 is the shortest length of a subarray with sum equal to target = 4. </pre> <p><strong class="example">Example 3:</strong></p> <pre> <strong>Input:</strong> nums = [2,4,6,8], target = 3 <strong>Output:</strong> -1 <strong>Explanation:</strong> In this example infinite_nums = [2,4,6,8,2,4,6,8,...]. It can be proven that there is no subarray with sum equal to target = 3. </pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>1 <= nums.length <= 10<sup>5</sup></code></li> <li><code>1 <= nums[i] <= 10<sup>5</sup></code></li> <li><code>1 <= target <= 10<sup>9</sup></code></li> </ul>