{ "data": { "question": { "questionId": "3181", "questionFrontendId": "2940", "boundTopicId": null, "title": "Find Building Where Alice and Bob Can Meet", "titleSlug": "find-building-where-alice-and-bob-can-meet", "content": "
You are given a 0-indexed array heights
of positive integers, where heights[i]
represents the height of the ith
building.
If a person is in building i
, they can move to any other building j
if and only if i < j
and heights[i] < heights[j]
.
You are also given another array queries
where queries[i] = [ai, bi]
. On the ith
query, Alice is in building ai
while Bob is in building bi
.
Return an array ans
where ans[i]
is the index of the leftmost building where Alice and Bob can meet on the ith
query. If Alice and Bob cannot move to a common building on query i
, set ans[i]
to -1
.
\n
Example 1:
\n\n\nInput: heights = [6,4,8,5,2,7], queries = [[0,1],[0,3],[2,4],[3,4],[2,2]]\nOutput: [2,5,-1,5,2]\nExplanation: In the first query, Alice and Bob can move to building 2 since heights[0] < heights[2] and heights[1] < heights[2]. \nIn the second query, Alice and Bob can move to building 5 since heights[0] < heights[5] and heights[3] < heights[5]. \nIn the third query, Alice cannot meet Bob since Alice cannot move to any other building.\nIn the fourth query, Alice and Bob can move to building 5 since heights[3] < heights[5] and heights[4] < heights[5].\nIn the fifth query, Alice and Bob are already in the same building. \nFor ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet.\nFor ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.\n\n\n
Example 2:
\n\n\nInput: heights = [5,3,8,2,6,1,4,6], queries = [[0,7],[3,5],[5,2],[3,0],[1,6]]\nOutput: [7,6,-1,4,6]\nExplanation: In the first query, Alice can directly move to Bob's building since heights[0] < heights[7].\nIn the second query, Alice and Bob can move to building 6 since heights[3] < heights[6] and heights[5] < heights[6].\nIn the third query, Alice cannot meet Bob since Bob cannot move to any other building.\nIn the fourth query, Alice and Bob can move to building 4 since heights[3] < heights[4] and heights[0] < heights[4].\nIn the fifth query, Alice can directly move to Bob's building since heights[1] < heights[6].\nFor ans[i] != -1, It can be shown that ans[i] is the leftmost building where Alice and Bob can meet.\nFor ans[i] == -1, It can be shown that there is no building where Alice and Bob can meet.\n\n\n\n
\n
Constraints:
\n\n1 <= heights.length <= 5 * 104
1 <= heights[i] <= 109
1 <= queries.length <= 5 * 104
queries[i] = [ai, bi]
0 <= ai, bi <= heights.length - 1
[x, y]
, if x > y
, swap x
and y
. Now, we can assume that x <= y
.",
"For each query [x, y]
, if x == y
or heights[x] < heights[y]
, then the answer is y
since x ≤ y
.",
"Otherwise, we need to find the smallest index t
such that y < t
and heights[x] < heights[t]
. Note that heights[y] <= heights[x]
, so heights[x] < heights[t]
is a sufficient condition.",
"To find index t
for each query, sort the queries in descending order of y
. Iterate over the queries while maintaining a monotonic stack which we can binary search over to find index t
."
],
"solution": null,
"status": null,
"sampleTestCase": "[6,4,8,5,2,7]\n[[0,1],[0,3],[2,4],[3,4],[2,2]]",
"metaData": "{\n \"name\": \"leftmostBuildingQueries\",\n \"params\": [\n {\n \"name\": \"heights\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer[][]\",\n \"name\": \"queries\"\n }\n ],\n \"return\": {\n \"type\": \"integer[]\"\n }\n}",
"judgerAvailable": true,
"judgeType": "large",
"mysqlSchemas": [],
"enableRunCode": true,
"enableTestMode": false,
"enableDebugger": true,
"envInfo": "{\"cpp\": [\"C++\", \"Compiled with clang 11
using the latest C++ 20 standard.
Your code is compiled with level two optimization (-O2
). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
\"], \"java\": [\"Java\", \"OpenJDK 17
. Java 8 features such as lambda expressions and stream API can be used.
Most standard library headers are already included automatically for your convenience.
\\r\\nIncludes Pair
class from https://docs.oracle.com/javase/8/javafx/api/javafx/util/Pair.html.
Python 2.7.12
.
Most libraries are already imported automatically for your convenience, such as array, bisect, collections. If you need more libraries, you can import it yourself.
\\r\\n\\r\\nFor Map/TreeMap data structure, you may use sortedcontainers library.
\\r\\n\\r\\nNote that Python 2.7 will not be maintained past 2020. For the latest Python, please choose Python3 instead.
\"], \"c\": [\"C\", \"Compiled with gcc 8.2
using the gnu11 standard.
Your code is compiled with level one optimization (-O1
). AddressSanitizer is also enabled to help detect out-of-bounds and use-after-free bugs.
Most standard library headers are already included automatically for your convenience.
\\r\\n\\r\\nFor hash table operations, you may use uthash. \\\"uthash.h\\\" is included by default. Below are some examples:
\\r\\n\\r\\n1. Adding an item to a hash.\\r\\n
\\r\\nstruct hash_entry {\\r\\n int id; /* we'll use this field as the key */\\r\\n char name[10];\\r\\n UT_hash_handle hh; /* makes this structure hashable */\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n HASH_ADD_INT(users, id, s);\\r\\n}\\r\\n\\r\\n\\r\\n\\r\\n
2. Looking up an item in a hash:\\r\\n
\\r\\nstruct hash_entry *find_user(int user_id) {\\r\\n struct hash_entry *s;\\r\\n HASH_FIND_INT(users, &user_id, s);\\r\\n return s;\\r\\n}\\r\\n\\r\\n\\r\\n\\r\\n
3. Deleting an item in a hash:\\r\\n
\\r\\nvoid delete_user(struct hash_entry *user) {\\r\\n HASH_DEL(users, user); \\r\\n}\\r\\n\\r\\n\"], \"csharp\": [\"C#\", \"\"], \"javascript\": [\"JavaScript\", \"
Node.js 16.13.2
.
Your code is run with --harmony
flag, enabling new ES6 features.
lodash.js library is included by default.
\\r\\n\\r\\nFor Priority Queue / Queue data structures, you may use 5.3.0 version of datastructures-js/priority-queue and 4.2.1 version of datastructures-js/queue.
\"], \"ruby\": [\"Ruby\", \"Ruby 3.1
Some common data structure implementations are provided in the Algorithms module: https://www.rubydoc.info/github/kanwei/algorithms/Algorithms
\"], \"swift\": [\"Swift\", \"Swift 5.5.2
.
Go 1.21
Support https://godoc.org/github.com/emirpasic/gods@v1.18.1 library.
\"], \"python3\": [\"Python3\", \"Python 3.10
.
Most libraries are already imported automatically for your convenience, such as array, bisect, collections. If you need more libraries, you can import it yourself.
\\r\\n\\r\\nFor Map/TreeMap data structure, you may use sortedcontainers library.
\"], \"scala\": [\"Scala\", \"Scala 2.13.7
.
Kotlin 1.9.0
.
Rust 1.58.1
Supports rand v0.6\\u00a0from crates.io
\"], \"php\": [\"PHP\", \"PHP 8.1
.
With bcmath module
\"], \"typescript\": [\"Typescript\", \"TypeScript 5.1.6, Node.js 16.13.2
.
Your code is run with --harmony
flag, enabling new ES2022 features.
lodash.js library is included by default.
\"], \"racket\": [\"Racket\", \"Run with Racket 8.3
.
Dart 2.17.3
\\r\\n\\r\\nYour code will be run directly without compiling
\"]}", "libraryUrl": null, "adminUrl": null, "challengeQuestion": null, "__typename": "QuestionNode" } } }