{ "data": { "question": { "questionId": "383", "questionFrontendId": "383", "categoryTitle": "Algorithms", "boundTopicId": 1656, "title": "Ransom Note", "titleSlug": "ransom-note", "content": "

Given two strings ransomNote and magazine, return true if ransomNote can be constructed from magazine and false otherwise.

\n\n

Each letter in magazine can only be used once in ransomNote.

\n\n

 

\n

Example 1:

\n
Input: ransomNote = \"a\", magazine = \"b\"\nOutput: false\n

Example 2:

\n
Input: ransomNote = \"aa\", magazine = \"ab\"\nOutput: false\n

Example 3:

\n
Input: ransomNote = \"aa\", magazine = \"aab\"\nOutput: true\n
\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "赎金信", "translatedContent": "

给你两个字符串：ransomNote 和 magazine ，判断 ransomNote 能不能由 magazine 里面的字符构成。

\n\n

如果可以，返回 true ；否则返回 false 。

\n\n

magazine 中的每个字符只能在 ransomNote 中使用一次。

\n\n

 

\n\n

示例 1：

\n\n
\n输入：ransomNote = \"a\", magazine = \"b\"\n输出：false\n
\n\n

示例 2：

\n\n
\n输入：ransomNote = \"aa\", magazine = \"ab\"\n输出：false\n
\n\n

示例 3：

\n\n
\n输入：ransomNote = \"aa\", magazine = \"aab\"\n输出：true\n
\n\n

 

\n\n

提示：

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