{ "data": { "question": { "questionId": "3218", "questionFrontendId": "2973", "categoryTitle": "Algorithms", "boundTopicId": 2575542, "title": "Find Number of Coins to Place in Tree Nodes", "titleSlug": "find-number-of-coins-to-place-in-tree-nodes", "content": "

You are given an undirected tree with n nodes labeled from 0 to n - 1, and rooted at node 0. You are given a 2D integer array edges of length n - 1, where edges[i] = [ai, bi] indicates that there is an edge between nodes ai and bi in the tree.

\n\n

You are also given a 0-indexed integer array cost of length n, where cost[i] is the cost assigned to the ith node.

\n\n

You need to place some coins on every node of the tree. The number of coins to be placed at node i can be calculated as:

\n\n\n\n

Return an array coin of size n such that coin[i] is the number of coins placed at node i.

\n\n

 

\n

Example 1:

\n\"\"\n
\nInput: edges = [[0,1],[0,2],[0,3],[0,4],[0,5]], cost = [1,2,3,4,5,6]\nOutput: [120,1,1,1,1,1]\nExplanation: For node 0 place 6 * 5 * 4 = 120 coins. All other nodes are leaves with subtree of size 1, place 1 coin on each of them.\n
\n\n

Example 2:

\n\"\"\n
\nInput: edges = [[0,1],[0,2],[1,3],[1,4],[1,5],[2,6],[2,7],[2,8]], cost = [1,4,2,3,5,7,8,-4,2]\nOutput: [280,140,32,1,1,1,1,1,1]\nExplanation: The coins placed on each node are:\n- Place 8 * 7 * 5 = 280 coins on node 0.\n- Place 7 * 5 * 4 = 140 coins on node 1.\n- Place 8 * 2 * 2 = 32 coins on node 2.\n- All other nodes are leaves with subtree of size 1, place 1 coin on each of them.\n
\n\n

Example 3:

\n\"\"\n
\nInput: edges = [[0,1],[0,2]], cost = [1,2,-2]\nOutput: [0,1,1]\nExplanation: Node 1 and 2 are leaves with subtree of size 1, place 1 coin on each of them. For node 0 the only possible product of cost is 2 * 1 * -2 = -4. Hence place 0 coins on node 0.\n
\n\n

 

\n

Constraints:

\n\n\n", "translatedTitle": "树中每个节点放置的金币数目", "translatedContent": "

给你一棵 n 个节点的 无向 树，节点编号为 0 到 n - 1 ，树的根节点在节点 0 处。同时给你一个长度为 n - 1 的二维整数数组 edges ，其中 edges[i] = [ai, bi] 表示树中节点 ai 和 bi 之间有一条边。

\n\n

给你一个长度为 n 下标从 0 开始的整数数组 cost ，其中 cost[i] 是第 i 个节点的 开销 。

\n\n

你需要在树中每个节点都放置金币，在节点 i 处的金币数目计算方法如下：

\n\n\n\n

请你返回一个长度为 n 的数组 coin ，coin[i]是节点 i 处的金币数目。

\n\n

 

\n\n

示例 1：

\n\n

\"\"

\n\n
\n输入：edges = [[0,1],[0,2],[0,3],[0,4],[0,5]], cost = [1,2,3,4,5,6]\n输出：[120,1,1,1,1,1]\n解释：在节点 0 处放置 6 * 5 * 4 = 120 个金币。所有其他节点都是叶子节点，子树中只有 1 个节点，所以其他每个节点都放 1 个金币。\n
\n\n

示例 2：

\n\n

\"\"

\n\n
\n输入：edges = [[0,1],[0,2],[1,3],[1,4],[1,5],[2,6],[2,7],[2,8]], cost = [1,4,2,3,5,7,8,-4,2]\n输出：[280,140,32,1,1,1,1,1,1]\n解释：每个节点放置的金币数分别为：\n- 节点 0 处放置 8 * 7 * 5 = 280 个金币。\n- 节点 1 处放置 7 * 5 * 4 = 140 个金币。\n- 节点 2 处放置 8 * 2 * 2 = 32 个金币。\n- 其他节点都是叶子节点，子树内节点数目为 1 ，所以其他每个节点都放 1 个金币。\n
\n\n

示例 3：

\n\n

\"\"

\n\n
\n输入：edges = [[0,1],[0,2]], cost = [1,2,-2]\n输出：[0,1,1]\n解释：节点 1 和 2 都是叶子节点，子树内节点数目为 1 ，各放置 1 个金币。节点 0 处唯一的开销乘积是 2 * 1 * -2 = -4 。所以在节点 0 处放置 0 个金币。\n
\n\n

 

\n\n

提示：

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This can be done by using two Heaps with the size of at most three.", "You need to store at most six values at each subtree.", "If there are more than three values in total, we can sort them. Let’s call the resultant array A, the maximum product of three is max(A[0] * A[1] * A[n - 1], A[n - 1] * A[n - 2] * A[n - 3]). Don’t forget to set the result to 0 if the value is negative.", "If there are less than three values for a subtree, set its result to 1." ], "solution": null, "status": null, "sampleTestCase": "[[0,1],[0,2],[0,3],[0,4],[0,5]]\n[1,2,3,4,5,6]", "metaData": "{\n \"name\": \"placedCoins\",\n \"params\": [\n {\n \"name\": \"edges\",\n \"type\": \"integer[][]\"\n },\n {\n \"type\": \"integer[]\",\n \"name\": \"cost\"\n }\n ],\n \"return\": {\n \"type\": \"long[]\"\n }\n}", "judgerAvailable": true, "judgeType": "large", "mysqlSchemas": [], "enableRunCode": true, "envInfo": "{\"cpp\":[\"C++\",\"

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