<p>We have an array of integers, <code>nums</code>, and an array of <code>requests</code> where <code>requests[i] = [start<sub>i</sub>, end<sub>i</sub>]</code>. The <code>i<sup>th</sup></code> request asks for the sum of <code>nums[start<sub>i</sub>] + nums[start<sub>i</sub> + 1] + ... + nums[end<sub>i</sub> - 1] + nums[end<sub>i</sub>]</code>. Both <code>start<sub>i</sub></code> and <code>end<sub>i</sub></code> are <em>0-indexed</em>.</p> <p>Return <em>the maximum total sum of all requests <strong>among all permutations</strong> of</em> <code>nums</code>.</p> <p>Since the answer may be too large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p> <p> </p> <p><strong>Example 1:</strong></p> <pre> <strong>Input:</strong> nums = [1,2,3,4,5], requests = [[1,3],[0,1]] <strong>Output:</strong> 19 <strong>Explanation:</strong> One permutation of nums is [2,1,3,4,5] with the following result: requests[0] -> nums[1] + nums[2] + nums[3] = 1 + 3 + 4 = 8 requests[1] -> nums[0] + nums[1] = 2 + 1 = 3 Total sum: 8 + 3 = 11. A permutation with a higher total sum is [3,5,4,2,1] with the following result: requests[0] -> nums[1] + nums[2] + nums[3] = 5 + 4 + 2 = 11 requests[1] -> nums[0] + nums[1] = 3 + 5 = 8 Total sum: 11 + 8 = 19, which is the best that you can do. </pre> <p><strong>Example 2:</strong></p> <pre> <strong>Input:</strong> nums = [1,2,3,4,5,6], requests = [[0,1]] <strong>Output:</strong> 11 <strong>Explanation:</strong> A permutation with the max total sum is [6,5,4,3,2,1] with request sums [11].</pre> <p><strong>Example 3:</strong></p> <pre> <strong>Input:</strong> nums = [1,2,3,4,5,10], requests = [[0,2],[1,3],[1,1]] <strong>Output:</strong> 47 <strong>Explanation:</strong> A permutation with the max total sum is [4,10,5,3,2,1] with request sums [19,18,10].</pre> <p> </p> <p><strong>Constraints:</strong></p> <ul> <li><code>n == nums.length</code></li> <li><code>1 <= n <= 10<sup>5</sup></code></li> <li><code>0 <= nums[i] <= 10<sup>5</sup></code></li> <li><code>1 <= requests.length <= 10<sup>5</sup></code></li> <li><code>requests[i].length == 2</code></li> <li><code>0 <= start<sub>i</sub> <= end<sub>i</sub> < n</code></li> </ul>